Answer:
option (c)
Explanation:
Fundamental frequency of segment A = f
Second harmonic frequency of B = fundamental frequency of A .
Tension in both the wires is same and the mass density is also same as the wires are identical.
fundamental frequency of wire A is given by
.... (1)
Second harmonic of B is given by
.... (2)
Equation (1) is equal to equation (2), we get


So, LB = 2 L
Thus, the length of wire segment B is 2 times the length of wire segment A.
Answer:
Δy= 5,075 10⁻⁶ m
Explanation:
The expression that describes the interference phenomenon is
d sin θ = (m + ½) λ
As the observation is on a distant screen
tan θ = y / x
tan θ= sin θ/cos θ
As in ethanes I will experience the separation of the vines is small and the distance to the big screen
tan θ = sin θ
Let's replace
d y / x = (m + ½) λ
The width of a bright stripe at the difference in distance
y₁ = (m + ½) λ x / d
m = 1
y₁ = 3/2 λ x / d
Let's use m = 1, we look for the following interference,
m = 2
y₂ = (2+ ½) λ x / d
The distance to the screen is constant x₁ = x₂ = x₀
The width of the bright stripe is
Δy = λ x / d (5/2 -3/2)
Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)
Δy= 5,075 10⁻⁶ m
Answer:
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Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;

where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Explanation:
Here,
Velocity of A=60km/hr
Velocity of B=80km/hr
Now,
Relative velocity of B with respect to A in the same direction=Velocity of B - Velocity of A
=80km/hr-60km/hr
=20km/hr