Answer:2
Step-by-step explanation: cot2θ+cosec2θ
=
=/1+cot²θ
=
=
=
=
Function, as it is y=
As there is no repeating x's it is a function
Dilation refers to a non rigid motion where a figure is transform and its image has the same form but a different size measure.Dilation is define by the rule (x,y)-- (kx, ky) where k represents the scale factor.
On this exercise is given that a triangle with vertices A(-6,-3), B(7,-7), and C(0,3) was dilated by a scale factor of 1.5, and it is asked to find the vertices of the image of the triangle after the dilation occurred.
Pre-image Image
A(-6,-3) --- (-6*1.5,-3*1.5) --- A'(-9,-4.5)
B(7,-7) ---- (7*1.5,-7*1.5) ---- B'(10.5,-10.5)
C(0,3) ----- (0*1.5,3*1.5) ----- C'(0,4.5)
The coordinates of the triangle's image after a dilation with a scale factor of 1.5 are represented by the points A'(-9,-4.5), B'(10.5,-10.5), and C'(0,4.5).
Answer:
7.2/3 ± (isqrt2)/3
8.2±i
9.-0.4±0.2
10.1/3±1/3sqrt19
Step-by-step explanation:
7. a =3, b=-4, c=2
plugging in to the quadratic formula
(2 ± isqrt2)/3
8.a=1,b=-4.c=5
plugging in to the quadratic formula
2±i
9.a=5,b=4,c=2
plugging in to the quadratic formula
-0.4±0.2
10.a=-3,b=2,c=6
plugging in to the quadratic formula
1/3±1/3sqrt19
Answer:
Step-by-step explanation:
these are two different questions .
first i solve first
position of submarine= -250/3 meters below see level
height descended=120 % of 250/3=120/100 ×(250/3)=300,00/300=100 m
new location=-250/3+(-100)=-650/3 below see level.
2nd question
position of submarine=-250 2/3=-752/3 m below see level
height descended=120 5/8=965/8 m =-965/8 m below see level
new positin=-752/3+(-965/8)=-(6016+2895)/24=-8911/24=-371 7/24m below sesa level.