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Burka [1]
3 years ago
6

Help me please! What is the median of this data? 48, 60, 22, 84, 36

Mathematics
2 answers:
vova2212 [387]3 years ago
3 0
He is wrong. You first need to put it in order before getting the middle. Like so:
22, 36, 48, 60, 84
Now cross out 22, then 84, and so on till you're left with one number (the middle number)

THE ANSWER IS 48
Free_Kalibri [48]3 years ago
3 0
22 because the median is just the middle number of a set of data
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Step-by-step explanation:

Given,

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Critical value =\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]  

                                                =1-0.90

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Critical value =\frac{z_{0.1}}{2}

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The margin of error (E)  =\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }

                                       =1.645\times\frac{1.90}{\sqrt{41} }

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Hence, The margin of error (E) =0.49

Complete question is attached in below.

                     

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