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3 years ago

What is mean, median, mode and range? Below are words to a song that will

Mathematics

1 answer:

Ganezh [65]3 years ago

8 0

Highest value and lowest value

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Find the midpoint of A and B where A has coordinates (2, 4)<br> and B has coordinates (-3, -9).

tatuchka [14]

Answer:

(-0.5,-2.5)

Step-by-step explanation:

(x1 + x2) / 2 = x midpoint
(y1 + y2) / 2 = y midpoint

⇒ 2 + -3 = 5

⇒ 5 / 2 = -0.5

⇒ 4 + -9 = -5

⇒ -5 / 2 = -2.5

→ = (-0.5, -2.5)

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2 years ago

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Triangle DEF contains two congruent acute angles. The sum of the measures of the two congruent acute angles is greater than 90 d

lana66690 [7]

B. <span>She is correct. The remaining angle of the triangle measures less than 90 degrees.</span>

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2 years ago

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The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

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3 years ago

Solve for x.<br> 4x +4=12

PolarNik [594]

Answer:

x = 2

Step-by-step explanation:

4x +4=12

-4. -4

4x.= 8

divide both saide by 4

x. = 2

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3 years ago

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siniylev [52]

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2 years ago