When the firecracker hits the ground, H(t) = 0.0 = -16t^2 + 90t + 160 Using the quadratic formula,t = (-90 +- sqrt(90^2 - 4(-16)(160))) / 2(-16)t = -1.42 ort = 7.04
The negative time is extraneous. Therefore,t = 7.04 s.
Seven Seconds is your answer!
The correct answer is:
<span>
The graph shifts 5 units right
Explanation:
Below is the graph attached of both the equations:
Red line: Represents f(x) = </span><span>2x + 2.
Blue line: Represents g(x) = 2x - 3.
As you can see in the graph that g(x) is shifted 5 units right to f(x).
If you move towards right by 1 unit, you have to subtract 1 from f(x) until you reach g(x) like:
2x + 2 - 1 = 2x + 1 (1 unit)
</span>2x + 1 - 1 = 2x (1 unit)
2x - 1 = 2x - 1 (1 unit)
2x - 1 -1 = 2x - 2 (1 unit)
2x -2 - 1 = 2x -3 (1 unit)
Total 5 units.
Hence the correct answer is
t<span>
he graph shifts 5 units right.</span>
From 6,1 to 7,4
We can determine the slope of the line
rise/run
3/1=3
Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A
(-4,1) and (-2,7)
they drunk 2/3 because 3/4=9/12-8/12=1/12 and 8/12 is equal to 2/3 so 2/3 is your answer. Hope this helps!