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Answer:
18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.
This means that
Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
This is P(X = 3).
18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year
Answer:
The 99% confidence interval is (0.0787, 0.1613).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of .
For this problem, we have that:
The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating. This means that
The 99% confidence interval is
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval is (0.0787, 0.1613).