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3 years ago

53x52 step by step plzzz

Mathematics

1 answer:

Zigmanuir [339]3 years ago

3 0

Answer: here you go i tried my best

Step-by-step explanation:

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Help me please. How to prove this ?

podryga [215]

Answer:

First, you want to divide the numerator and denominator by the cosine(x), and afterwards, it looks like this...

$\frac{tan~x+1}{tan~x-1}$

Include 45 as one of the parameters and correlate with tan.

$\frac{tan~x+tan~45}{tan~x-tan~45}$

Next, you want to multiply the numerator and denominator by the conjugate of the denominator, in this case, tan x + tan 45.

Lastly, simplify, and you have the answer as tan(45 + x)

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2 years ago

Heyyyyy pleasse help me please please and thank you

dimulka [17.4K]

Answer:

x ≈ 33.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = $\frac{opposite}{adjacent}$ = $\frac{125}{192}$ , then

x = $tan^{-1}$ ( $\frac{125}{192}$ ) ≈ 33.1° ( to the nearest tenth )

7 0

2 years ago

in the first 1/2 mile of the trail, Jayden posts 3 signs that describe local birds. If the signs are equal distance apart , What

My name is Ann [436]

1/2 of a mile is divided equally into 3 parts- we need to find the distance between the second and third sign.

1/2 x 1/3 is 1/6.

This means that each sign is 1/6th of a mile apart.

If you have further confusions about the question, please feel free to message me and I will help to the best of my ability!

Hope this Helps!
-Sinnamin

8 0

3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$