1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
3 years ago
9

I need help someone help

Mathematics
2 answers:
oee [108]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The sum of 8 and 5

(8 + 5)

11 times the sum of 8 and 5

11 x (8 + 5)

Tanzania [10]3 years ago
4 0

Answer:

The correct answer is D

Step-by-step explanation:

It's d because the 8+5 is in parenthesis that means you do that first before multiplying since the keyword is "sum".

You might be interested in
I am kinda new here. I joined a few days ago because I wanted to help. I have a question. Can we post any questions on Brainly?
frosja888 [35]

Answer:

yeah most likely

Step-by-step explanation:

<h2>MARK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz</h2>
3 0
3 years ago
Read 2 more answers
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
What is the midpoint of 10 and 20
erica [24]

Answer:

15

Step-by-step explanation:

Simply subtract the smaller number from the bigger number, and divide by 2. Or add the two numbers together and divide by 2.

6 0
2 years ago
Read 2 more answers
Element X is a radioactive isotope such that every 66 years, its mass
LenKa [72]

Answer:

194.5315427 grams

Step-by-step explanation:

The half-life of element x would be 66 years. So, after 20 years you would have:

.5^(20/66) x 240=0.810548 x 240

        =194.5315427 grams of the element left ......

3 0
3 years ago
Please help I’m a little confused
Mariana [72]

Answer:

1440°

Step-by-step explanation:

n = number of sides

n-2 x 180

10 - 2 = 8

8 x 180 = 1440°

4 0
3 years ago
Other questions:
  • Factor the expression 10x+40
    11·1 answer
  • what is the answer to this problem. lily built an orange shelf and a brown shelf to hang in her room. the orange shelf is 5 feet
    8·1 answer
  • Show how the perfect numbers 6 and 28 were generated. Show the aliquot parts of 6 and 28
    6·1 answer
  • A distance of 200 meters in 25 seconds is ran what is the average speed of a sprinter
    5·2 answers
  • Solve the proportion
    6·1 answer
  • 5. What is the value of x?<br> A)15 Square root 3 B)15/2 C)5 Square root 3 D)15 Square root 2/2
    11·1 answer
  • Which of the following best approximates the line of best fit?
    13·2 answers
  • carter has a collection of 37 coins found while walking home. All of Carter coins are either nickels or dimes. The value of the
    5·1 answer
  • HELP ME QUICKLY!!!!!!!!!!!!!!!It takes Luis 15
    11·2 answers
  • Which of the following theorems verifies that LMN = ABC
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!