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3 years ago

PLS help will give brainliest fill in the blanks only do it if you know its CORRECT

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

3 5 = 16

3 = 3 16

6 = 16

6 = -4

x = -4/6

each line has the number of boxes to be filled

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Complete the pairs of corresponding parts if △RST ≅ △TXY.

ELEN [110]

Answer:

∡S corresponds to ∡X

∡TXY = ∡RST

∡XTY = ∡SRT

∡XYT = ∡STR

Step-by-step explanation:

7 0

3 years ago

Match the logarithmic functions with their corresponding x-values

cricket20 [7]

We have the following functions:
log2x=5
log10x=3
log4x=2
log3x=1
log5x=4
Let's rewrite each function to solve for x:
x=2^5=32
x=10^3=1000
x=4^2=16
x=3^1=3
x=5^4=625
Answer:
Matching each function with the solution we have:
log2x=5 ----------->32
log10x=3---------->1000
log4x=2------------>16
log5x=4------------>625

3 0

3 years ago

Maya is helping a gardener plant 300 bulbs. They plant 20% of the bulbs on Monday and 30% of the bulbs on Tuesday. Maya says thi

Katyanochek1 [597]

Answer:

because the total is 300 not 100 so 50 is not reasonable because that is the percentage they planted and since it is more than 100 then it should be a percent of 300 not 100. Maya is wrong about placing 50 bulbs instead they placed 150.

Step-by-step explanation:

8 0

3 years ago

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago

Find the area of the composite shape. Make sure to show your work.

earnstyle [38]

Answer:

I'm not sure

Step-by-step explanation:

sorry lol :(

4 0

3 years ago