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Taya2010 [7]
3 years ago
11

Which would easily give up more electrons during bonding? Use Periodic Table.

Chemistry
1 answer:
Serjik [45]3 years ago
8 0

Answer:

I'm pretty sure that it's lithium because it gives up one of their 3 electrons, so li

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Why are many fossil remains left from the last ice age
Vaselesa [24]
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8 0
3 years ago
Determine which equations you would use to solve the following problem: Calculate the amount of heat needed to change 20.0 g of
Inessa [10]

Answer:

Q = 4019.4 J

Explanation:

Given data:

Mass of ice = 20.0 g

Initial temperature = -10°C

Final temperature = 89.0°C

Amount of heat required = ?

Solution:

specific heat capacity of ice is 2.03 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT =  89.0°C - (-10°C)

ΔT = 99°C

Q = 20.0 g ×2.03 J/g.°C × 99°C

Q = 4019.4 J

3 0
3 years ago
Structure for reductive ozonolysis of 3,5-dimethyl-4-octene​
brilliants [131]

Answer:

Scheme is Attached.

When 3,5 dimethyl-4- octene is react with ozone two products are obtain.

2-Methyl butanal and 2 pentanon.

The complete reaction is given in attached file.

3 0
3 years ago
What is the best definition of energy?
tatuchka [14]

Answer:

C

this answer needs to be 20 characters long

5 0
3 years ago
Read 2 more answers
La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)
Neko [114]

Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

6 0
3 years ago
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