Which would easily give up more electrons during bonding? Use Periodic Table.
1 answer:
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Answer:
not aromatic
Explanation:
Cyclopropene -
as the compound is is made to lose a proton , and gains a negative charge on its ring ,
Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,
According to Huckel 's rule ,
The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,
And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.
Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .
Therefore , the compound becomes not aromatic or anti - aromatic .
