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quester [9]
3 years ago
10

What is the arrhenius definition of a base?

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
4 0
The Arrhenius definition of acid-base reactions, which was devised by Svante Arrhenius, is a development of the hydrogen theory of acids. ... An Arrhenius base is a substance that dissociates in water to form hydroxide (OH -) ions. In other words, a base increases the concentration of OH - ions in an aqueous solution.
vaieri [72.5K]3 years ago
3 0

A substance that increases H3O+ concentration when it is dissolved in water.

A substance that increases OH– concentration when it is dissolved in water.

A compound that donates protons.

A compound that accepts protons.


it is the last option

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3 years ago
H2SO4 is a strong acid because the first proton ionizes 100%. The Ka of the second proton is 1.1x10-2. What would be the pH of a
forsale [732]

Question options:

a) 2.05

b) 0.963

c) 0.955

d) 1.00

Answer:

b) 0.963

Explanation:

H2SO4→ HSO4- + H3O+

HSO4- + H2O ⇌ SO42- + H3O+

Construct ICE table:

        HSO4- (aq)    +    H2O        ⇌      SO42- (aq)     +     H3O+ (aq)

I          0.1                  solid &                   0                          0.1

C         -x                     liquid                 + x                            + x

E         0.1 - x          are ignored              x                          0.1 + x

Calculate x

Ka = products/reactants

  = \frac{[SO42-] [H3O+]}{[HSO4-]}

0.011 = \frac{x (0.1 + x)}{0.1 - x}

0.011 x (0.1 -x) = o.1x + x^2

0.0011 - 0.011 x - o.1x - x^2 = 0

0.0011 - 0.011 x - x^2 = 0

Use formula to solve for quadratic equation

x = { -b +,-\sqrt{b^2 - 4ac / 2a

a = -1, b = -0.111, c = 0.001

Solve for x

x = \sqrt[-(-o.111)]{(-0.111)^2 - 4(-1) (0.0011) }  / 2(-1)

x = 0.111 +,- \sqrt{0.012321 + 0.0044} / -2

x = 0.111 +,- \sqrt{0.016721} / -2

x = \frac{0.111 +, - 0.1293}{-2}

x = \frac{0.111 + 0.1293}{-2}   , x = \frac{0.111  - 0.1293}{-2}

x = \frac{0.2403}{-2}    , x = \frac{0.0183}{-2}

x = - 0.12015  , x = 0.00915

x cannot be negative, so

x = 0.00915 M

Calculate [H3O+]

[H3O+] = 0.1 M + x

[H3O+] = 0.1 M + 0.00915 M

[H3O+] = 0.10915 M

Clculate pH

pH = - log [ H3O+]

pH = - log [ 0.10915]

pH = 0.963

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3 years ago
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