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Leya [2.2K]
3 years ago
7

Give the structure of the product obtained when cyclopropene loses a proton. Will the product be aromatic or not?

Chemistry
1 answer:
astra-53 [7]3 years ago
3 0

Answer:

not aromatic

Explanation:

Cyclopropene -

as the compound is is made to lose a proton , and gains a negative charge on its ring ,

Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,

According to Huckel 's rule ,

The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,

And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.

Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .

Therefore , the compound becomes not aromatic or anti - aromatic .

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a.

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Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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Moles =Molarity \times {Volume\ of\ the\ solution}

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b.

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

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c.

1.159 g of sample contains 0.296 g of acetylsalicylic acid

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