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saul85 [17]
3 years ago
11

ATRCCR-12 cmRE11TI-IV.VE-CEEAAT​

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

i think those are cord nits correct me if im wrong i might be

Step-by-step explanation:

You might be interested in
A recent survey of 128 high school students indicated the following information about release times from school. -35 percent wan
wlad13 [49]

Answer:

The interval is for those that want to get out earlier is between 43 student to 47 students

The interval is for those that want to get out later is between 48 student to 50 students

Step-by-step explanation:

Given that:

sample size n=128

Probability of those  that want to get out earlier = 0.35.

The mean  =  n × probability = 0.35 × 128 = 44.8 ≈ 45

Margin of error = 4% = 0.04 × 44.8 = 1.79 ≈ 2

Therefore the interval = mean ± Margin of error = 45 ± 2 = (43, 47)

The interval is for those that want to get out earlier is between 43 student to 47 students

Probability of those  that want to get out later = 0.39.

The mean  =  n × probability = 0.39 × 128 = 49.92 ≈ 50

Margin of error = 4% = 0.04 × 50 =  2

Therefore the interval = mean ± Margin of error = 50 ± 2 = (48, 52)

The interval is for those that want to get out later is between 48 student to 50 students

the group that wants to get out of school earlier to win after all the votes are counted if those that have no opinion decide that they want to go earlier

5 0
3 years ago
Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

  • Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
3 years ago
743 times 295 answer please
Mamont248 [21]
The answer is 219,775
5 0
3 years ago
Read 2 more answers
3x/4 +2/3=x/3 find the exact answer to the simplest form
slega [8]
First, we need to get rid of the denominator. to do so, we will simply multiply all terms by 12 (which is the result of 3*4).
(3x/4)(12)+(2/3)(12)=(x/3)(12)
9x + 8 = 4x
then we will separate the variable in one side and solve to get its value
9x-4x = -8
5x = -8
x = -8/5
5 0
3 years ago
What is a formula for the nth term of the given sequence?
lakkis [162]

Answer: option D is the correct answer.

Step-by-step explanation:

The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.

The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a1 = 36

r = 12/36 = 4/12 = 1/3

Therefore, the formula for the nth term of the sequence is

an = 36 × 1/3^(n - 1)

an = 36 × 3^-1(n - 1)

an = 36 × 3^(-n + 1)

an = 36 × 3^(1 - n)

6 0
3 years ago
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