All categories

3 years ago

Point K is between J and L. If JL-162, what is JK? 4x+8 68-6 J K K L

Mathematics

1 answer:

VladimirAG [237]3 years ago

5 0

Answer:

JK = 72

Step-by-step explanation:

JL = JK + KL = (4x+8) + (6x-6) = 10x + 2 = 162

--> x = (162-2)/10 = 16

JK = 4x + 8 = 4 . 16 + 8 = 72

You might be interested in

A local store is offering 20% off regular priceiPods. The original price is $200, how much willthe iPod cost during the sale?

Tju [1.3M]

This is the answer :
100%-20%=80%
$\frac{80}{100} = \frac{x}{200} \\ x = \frac{200 \times 80}{100} = \frac{16000}{100} = 160$
the answer $160

8 0

3 years ago

A jeweler wants to minimize business costs and has found that the average cost in dollars per necklace is given by C(x)=0.5x^2-7

Vika [28.1K]

Answer:

The maximum cost is 41 dollars per necklace.

Step-by-step explanation:

The average cost in dollars/necklace is given by :

$C(x)=0.5x^2-7x+65.5$ .....(1)

Where

x is the number of necklaces that are created

To maximize the cost, find the value of x by putting dC/dx = 0

$\dfrac{d}{dx}(0.5x^2-7x+65.5)=0\\\\x-7=0\\\\x=7$

Now put the value of x = 7 in equation (1).

$C(x)=0.5(7)^2-7(7)+65.5\\\\=41\ \text{dollars per necklace}$

Hence, the maximum cost is 41 dollars per necklace.

8 0

3 years ago

I like to think of myself as the most lucky person out there. 'Why?' you may ask. My reasoning is quite simple, really. The reas

dusya [7]

That’s really nice man. I’m sure she’ll love it

5 0

3 years ago

A marble is selected at random from a jar containing 3 red marbles, 4 yellow marbles, and 6 green marbles. What is the probabi

alexgriva [62]

Answer: a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

Step-by-step explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

a) the marble is red?

Probability of getting a red marble = $\dfrac{3}{13}$

b) the marble is not yellow?

Probability of not getting yellow = $\dfrac{3+6}{13}=\dfrac{9}{13}$

c) the marble is either red or green?

Probability of getting either red or green = P(red) + P(green) = $\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}$

d) the marble is neither red nor green?

Probability of getting neither red nor green = P(getting yellow) = $\dfrac{4}{13}$

Hence, a) $\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}$

5 0

3 years ago

Find the proportion of test worth 50 points; test score of 40%

stellarik [79]

I THINK it is 20% i used a calculator to help me find m answer

8 0

3 years ago

Read 2 more answers