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nata0808 [166]
3 years ago
10

Which of these situations can be modeled by an exponential function?

Mathematics
1 answer:
Gwar [14]3 years ago
6 0

Answer:

B) A herd of lions whose numbers triple every decade.

Step-by-step explanation:

Situations that can be modeled by exponential functions:

A situation can be modeled by exponential functions when the change is a multiplication or a division, not a sum or subtractions.

In this question:

In option A, C and D the measures are a sum or subtractions, as the rate of change is always the same. So it rests option B as the answer, as tripling is multiplying by 3.

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The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1

<h3>Equation of a line</h3>

A line is the distance between two points

Given the equation of a line expressed as 10x + 2y = -2. Determine the slope

2y = -10x -2

y = -5x - 1

Slope of the line is -5

The equation of a line in point-slope form is y - y1 = m(x-x1)

Substitute the point and the slope of the parallel line

y - 12 = -5(x  - 0)
y - 12 = -5x
y = -5x + 12

Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12

Learn more on equation of a line  here: brainly.com/question/13763238

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2 years ago
Jestina has A apples, she gave 5 to her sister, enter an expression to represent the number of apples jestina has now!! (show wo
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Step-by-step explanation:

Jestina has A apples

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A community group is setting up 616 chairs in 22 equal rows for an
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Step-by-step explanation:

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Find the diameter of the object (6cm)
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Answer:

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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
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Year         Sam              Sally1:             X                    (3/2)X-10002:            (5/2)X-2000     2X-15003:             X/5+1000       X/4+1400Total         37X/10-1000    15X/4-1100
Since their investments are known to be equal, we equate the two totals and solve for X.37X/10-1000=15X/4-1100(150-148)X/40 = 1100-1000X/20=100X=2000
So Sam invested $2000 the first year.Sally invested X/4+1400=1900 in the last year.
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3 years ago
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