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Zepler [3.9K]
4 years ago
7

The Casey family uses up a 1/2 gallon jug of milk every 3 days. At what rate do they drink milk?

Mathematics
2 answers:
Scilla [17]4 years ago
8 0
1/6 Gallons a day or .166


vlada-n [284]4 years ago
8 0

Answer:

1/6

Step-by-step explanation:

1/2 divided by 3

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$90 with 25% off (SHOW WORK)
Ivahew [28]

Answer:

$22.5

Step-by-step explanation:

25% of $90

25% x 90

0.25 x 90

$22.5

4 0
3 years ago
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Whats the equation for this problem?
Marina86 [1]
I know that x is equal to 11 and i hope it helps you 
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7 0
4 years ago
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Help. Will mark brainiest
Nikitich [7]

Answer:

Step-by-step explanation:

The third, fifth and sixth expressions (from the top) are NOT polynomials, and the reason in each case is that the expression has one or more negative powers of x in it.

8 0
4 years ago
On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
4 years ago
In a 3 hour examination of 350 questions, there are 50 mathematics problems. if twice as much time should be allowed for each ma
Margarita [4]

Answer: 7 minutes

Step-by-step explanation:

350/50=7

3*2.3333=7

3 0
4 years ago
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