Answer:
You have not added a picture soi can not help answer this question.
Step-by-step explanation:
Add the picture by either taking a photo or screenshot of the question then upload it.
First set up a linear equation and using the x and y values in the table see if it solves.
It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)
Using the quadratic formula y = ax^2 +bx +c
Build a set of 3 equations from the table:
C is the Y intercept ( when X is 0), this is shown in the table as 6
Now we have y = ax^2 + bx + 6
-2.4 =4a-2b +6
1.4 = a-b +6
Rewrite the equations
a=b/2 -2.1
1.4 = b/2-2.1 +6
b = 5
a = 5/2 -2.1 = 0.4
replace the letters to get y = 0.4x^2 + 5x +6
X= 70 degrees
Y= 70 degrees
Understand that every triangle has three angles and they add up to 180 degrees.
If I split this triangle in half the total degrees of each individual piece will be 90 degrees. A split in the isosceles triangle will also cause the 40 degrees to halved (thus, how I got 20 degrees in our 90 triangle).
Since we are dealing with an isosceles triangles two of the sides will be equal (hence, the dashes on the triangles sides). Therefore, x and y will also be equal.
Now if our 40 degreed angle is now 20 degrees, we have an unknown angle and the triangle in total now adds up to 90 degrees we can set up an equation.
20 + y = 90
Y = 70
Since X and Y are equal, X will also be 70.
If we return to to the isosceles triangle before it was split (use your photo for reference) and we add 40 +70 + 70 we will get 180 degrees. Which is the standard total of degrees for any triangle that is not a 90 degreed triangle.
I hope this helps. Feel free to ask questions.
Below I uploaded my work.
Answer:
19.0681
Step-by-step explanation:
Given in the question that,
angle from ted to the dog = 60° with the ground
height of ted from the ground = 16ft
To find,
distance between dog and the door of ted's building
Considering the scenario make a right angle triangle:
<h3>By using pythagorus theorem:</h3>
Tan 40 = opposite / adjacent
Tan 40 = height / distance between dog and the door
Tan 40 = 16ft / x
x = 16 / tan40
x = 19.068057
x ≈ 19.0681 (nearest to thousand)
So, the dog need to walk 19.0681ft to reach the open door directly below Ted.