In order to solve this question, we will need to know the E-field of a capacitor
E = sigma/epsilon naught
To find sigma (charge density), we will need to divide the total charge by the area
sigma = (.576 x 10^-9)/(4.952x10^-2)^2 = 2.34 x 10^-7
E = 2.34 x 10^-7/ (8.85x10^-12) = 26541.04 V/m
Answer:
Yeah it's the new trend lol it's kinda weird
When storm clouds produce lightening and thunder, then, potential energy changes into kinectic energy.
The clouds become negatively charged,and the ground is positively charged during a storm. So there creates a potential difference between the charged clouds and the ground. And when this becomes huge so much that it over comes the electrical insulation cover of air, the electrons jump to the ground.i.e. the potential energy changes into kinetic energy.
Answer:
Explanation:
a ) The volume of blood flowing per second throughout the vessel is constant .
a₁ v₁ = a₂ v₂
a₁ and a₂ are cross sectional area at two places of vessel and v₁ and v₂ are velocity of blood at these places .
2A x v₁ = A x .40
v₁ = .20 m /s
b )
Let normal pressure be P₁ when cross sectional area is 2A and at cross sectional area A , pressure is P₂
Applying Bernoulli's theorem
P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²
P₁ - P₂ = 1/2 ρ(v₂² - v₁² )
= .5 x 1060 ( .4² - .2² )
= 63.6 Pa .
