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iren [92.7K]
3 years ago
11

Which statement best explains the path light takes as it travels? A. Light takes a curved path through matter and takes a straig

ht path through space. B. Light moves in a straight line except at surfaces between different transparent materials, where its path bends. C. Light curves to spread out through openings and move around barriers.​
Physics
2 answers:
Misha Larkins [42]3 years ago
7 0

Answer:

The answer is B

Explanation:

I took the test for k12 and the answer was "Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

Hope this is helpful to anyone wondering what the answer is :)

Zolol [24]3 years ago
4 0

Answer:

it was "The light bends because it changes speed." for me i took the test

Explanation:

i show the thing. i hope this helps

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A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma
Dahasolnce [82]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{38}{57} =  \frac{2}{3}   \\  = 0.666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

4 0
3 years ago
a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector \bar A has component A_x = -5 m and A_y = 9 m

The magnitude of vector  \bar A can be represented as:

\bar A  = \sqrt{A_x^2 + A_y^2}

\bar A  = \sqrt{(-5)^2 + (9)^2}

\bar A  = \sqrt{25 + 81}

\bar A  = \sqrt{106}

\bar A  = 10.30 m

If we make \bar A  an angle \theta with y- axis:

Then;   tan \theta  = \frac{A_x}{A_y}

tan \theta  = \frac{5}{9}

tan \theta  = 0.555

\theta  = tan⁻¹ (0.555)

\theta  = 29.05°

Angle with positive x-axis = 90 + \theta  

= 90° + 29.05°

= 119.05°

5 0
3 years ago
Three metal spoons are on a table. They are each at room temperature. If the three spoons touch.
hoa [83]
If the three spoon touch nothing happens because they are all at room Temperature
3 0
3 years ago
Read 2 more answers
A student noted that the sign shown here is always associated with a wheelchair ramp at or near a staircase or entrance steps. W
Vitek1552 [10]

The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

  • <em>Let the height of the staircase = h</em>
  • <em>Let the length of the ramp = L</em>

The mechanical advantage of the ramp is calculated as follows;

M.A = \frac{L}{h}

As the length of the ramp increases, people will be move up to a greater distance up the staircase.

Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

Learn more about mechanical advantages of ramps here: brainly.com/question/200179

3 0
2 years ago
What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
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