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Fofino [41]
3 years ago
5

Two speakers emit sound waves with frequency 4.55 kHz. They are driven by the same oscillator so that they are in phase with eac

h other. I place the speakers side-by-side, and I stand across the room from them. If someone moves one of the speakers towards me, I hear the total intensity drop and then rise again. How far had they moved the speaker at the point where I heard a minimum intensity due to destructive interference of the sound waves from the two speakers? The speed of sound is 343 m/s
Physics
1 answer:
sergiy2304 [10]3 years ago
4 0

Answer:

d=3.76 cm

Explanation:

Given that frequency ,f= 4.55 KHz

Speed of sound = 343 m/s

We know that for sound

C= f λ

Where C is the velocity of sound

f is the frequency

λ is the wavelength

So now by putting the values

C= f λ

343= 4550 λ

λ=7.53 cm

We know that for destructive phase the difference in phase is π so the difference in distance will be λ/2.

So distance ,d= λ/2.

d=7.53/2 cm

d=3.76 cm

So they will move at a distance of 3.76 cm to hear minimum intensity of sound.

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<h3>Explanation</h3>

This question doesn't tell anything about how long it took for the car to go through 105 meters. As a result, the <em>timeless </em>suvat equation is likely what you need for this question.

In the <em>timeless</em> suvat equation,

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In this question,

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7 0
3 years ago
The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.
loris [4]
<u>Answer</u>

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<u>Explanation</u>
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Np/Ns = Vp/Vs

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Vp = (120 × 4)/10

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