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VikaD [51]
3 years ago
11

Hi please, I Have An attachment on Waves, Just two Objective Questions Whoever Answers Will be Marked Brainliest thank you.

Physics
1 answer:
kifflom [539]3 years ago
5 0

Answer:

The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.

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A manufacturer had 5 business locations. The producer always dealt with the manufacture's office manager for policy changes. The
Arturiano [62]
Tuberculosis. Reason: I just took the test and got it right
3 0
3 years ago
You have two golf balls that differ only in their surfaces. one has dimples, while the other is smooth. if you were to drop the
il63 [147K]

Answer: the golf ball with smooth surface would hit the ground first.


Jusitification:


An analysis of forces show two vertical forces acting on the golf balls.


1) one force is the weight (mg) which is vertical downward


2) the other force is the drag force exerted by the air on the golf balls, and it is vertical upward.


3) the drag force opposes the weight, so the acceleration downward is determined by the difference of the weiight and the drag force, until the balls reach the terminal speed (when the drag force equals the weight).


4) the drag force depends on the shape and area of the object falling. Being the surface of one ball smooth implies that the drag force will be less than the one on the other ball.


5) less drag force implies that the terminal velocity of the smooth ball will he higher, ant then it will hit the ground first.

3 0
3 years ago
An object at a distance of 6400km from the centre
Fittoniya [83]

Answer:

12.5N

Explanation:

From newton law of universal gravitation F= GmM/d2.

that means Force is inversely proportional to the square of the distance apart.

F1= 50N, d1=6400km

F2=?, d2=12800km

F1/F2=d2×d2/d1×d1 so we have 50/F2= 12800×12800/6400×6400...F2=6400×6400×50/(12800×12800)=12.5N

6 0
3 years ago
A thin flake of mica (n ! 1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the vi
Darina [25.2K]

Answer: 6.64 × 10^ -6 m

Explanation:

for a constructive interference;

ρ= 2πm

remember that we are looking for the seventh bright side fringe.

so, m=7

ρ=14π

We now have to find the phase different

ρ`=2πx/ρ - 2πx/ρ

p` is the wavelenght in the mica. x= width of the mica wavelength in the mica.

ρ= ρ/n.

n= refractive index.

The phase will now be

ρ`= 2πx/ρ - 2πx = 2πx(n-1)/ρ.

ρ= ρ`

14π = 2πx (n-1)/ ρ

we now solve for x; x = 7ρ/n-1

x = 7(550× 20^ 9)/ 1.58 - 1

= 6.64 × 10^-6

4 0
3 years ago
What is the mean distance between the Sun and the core of<br> the Milky Way?
sertanlavr [38]

Answer:

about 8 kpc

Explanation:

4 0
3 years ago
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