Answer:
Dipole-Dipole force
Explanation:
Dipole - Dipole force -
These are the force of attraction , that occurs between two dipole , i.e. ,a species with two poles , hence , the attraction between the delta positive charge of first species with the delta negative charge of the second species , arises to a dipole - dipole force of attraction.
Hence, from the question,
SO₂ , is a polar compound , where O is more electronegative in comparison to S , thus , O attains a delta negative charge and S attains a delta positive charge and therefore , generates a dipole , and interacts with the dipole of the second molecule of SO₂ , arising a dipole - dipole force of attraction .
Electrovalent or ionic bonding
Answer: option E. Evaporation to dryness
Explanation:
Easy!
All you have to do is look at the formula.
Lead Sulfide is PbS
Lead Oxide is PbO
Sulfur Dioxide is SO₂
Oxygen is O₂
You would need to balance out the equation, so it would be PbS + O₂ --> PbO + SO₂.
We can balance this out with the following. 2PbS + 2O₂ --> 2PbO + SO₂.
So 0.500 moles of oxygen would be the same conversion rate for PbO so it would also be 0.500 moles of lead oxide (PbO)
Answer:
A. Yes, Amanda find the number of moles of NaCl correctly.
B. 0.73 M.
Explanation:
<em>A. Did Amanda find the number of moles of NaCl correctly? If not, explain.
</em>
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Yes, Amanda find the number of moles of NaCl correctly.
- The relation to find the no. of moles of NaCl is:
<em>No. of moles (n) of NaCl = mass/molar mass.</em>
mass of NaCl = 32.0 g, molar mass of NaCl = 58.45 g/mol.
∴ No. of moles (n) of NaCl = mass/molar mass = (32.0 g)/(58.45 g/mol) = (32.0 g NaCl)*(1 mol of NaCl)/(58.45 g NaCl) = 0.547 mol ≅ 0.55 mol.
<em>B. What does Amanda need to do next to calculate the molarity of the NaCl solution? Show your work for full credit.</em>
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- Molarity is the no. of moles of solute dissolved in a 1.0 liter of a solution.
∴ M = (no. of moles of NaCl)/(volume of solution (L)) = (0.55 mol)/(0.75 L) = 0.73 M.