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Evgesh-ka [11]
3 years ago
10

Which of the following is not an example of predation?

Chemistry
1 answer:
swat323 years ago
8 0

Answer:

the flower big pollinated by The Bee and the receiving letter from the flower

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To begin the experiment, 1.11g of methane is burned in a bomb container containing 1000grams of water. The initial temperature i
PilotLPTM [1.2K]
The formula of heat added is presented as
Q = m * c * change in (T)

where 
Q - the heat added
m - mass
c - specific heat
<span>Change in temperature</span> - (Tf - To)

Basically, in order for us to know the change in heat, the formula is
Change in temperature = T(final) - T(original)
Change in temperature<span> = 36.65 - 24.85
</span>Change in temperature<span> = 11.8 degrees Celcius
</span>
So the change in temperature is 11.8 degrees 
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4 years ago
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GIVING BRAINIEST FIVE STARS AND HEART!
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How does thermal energy result from friction
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What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
x= x_{0}  e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t&#10;
and~ x_{0} ~the~original~amount.
when~x=  \frac{12.5}{100} x_{0}  }= \frac{125}{1000}  x_{0}
\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}
when t=19.8 hrs,&#10;x= x_{0}  e^{19.8 k}, &#10; \frac{x}{ x_{0} } = e^{19.8 k}, &#10; \frac{1}{8} = e^{19.8k} ,&#10;ln \frac{1}{8} =19.8 k,&#10;
ln1-ln8=19.8k,&#10;0-ln 2^{3} =19.8 k,&#10;-3 ln2=19.8k&#10;k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,&#10; \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } &#10;\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,&#10;2= e^{ \frac{ln2}{6.6}t } ,&#10;ln2=ln  e^{ \frac{ln 2}{6.6}t } = \frac{ln 2}{6.6} t~ln e= \frac{ln2}{6.6} t,
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4 years ago
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