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3 years ago

How many grams would 3.98 x 10^24 atoms of oxygen weigh

Chemistry

2 answers:

siniylev [52]3 years ago

8 0

Answer:

105.75 grams

Explanation:

(3.98 x 10^24 oxygen atoms) / (6.022 x 10^23 oxygen atoms * mol^-1) = 6.61 mol^-1

(6.61 mol^-1)(16.00 g*mol^-1) = 105.75 g

Semenov [28]3 years ago

4 0

Answer:

a little bit

Explanation:

i think

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3 years ago

How long would it take for 1.50 mol of water at 100.0 âc to be converted completely into steam if heat were added at a constant

defon

To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = 2260 J/g.

Molar mass of water = 18 g/mol

Q = mΔHvap = (1.50 mol water)(18 g/mol)(2260 J/g) = 61,020 J

Time = Q/Rate = (61,020 J)(1 s/20 J) = 3051 seconds

In order to express the answer in three significant units, let's convert that to minutes.
Time = 3051 s * 1min/30 s = 102 min

6 0

3 years ago

A colorless liquid has a molar mass of 60.01 g/mol. When the liquid was analyzed, it was 46.7% nitrogen and 53.3% oxygen. What i

MAXImum [283]

first we have to find the empirical formula of the compound

empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

therefore number of atoms are

N - 1

O - 1

empirical formula is - NO

mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

molecular formula is actual composition of elements in the compound

molecular mass - 60.01 g/mol

number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

there are 2 empirical units

2(NO)

molecular formula = N₂O₂

6 0

3 years ago

(WILL MARK BRAINLIEST) PLZ HELP ASAP

ArbitrLikvidat [17]

Answer:

a) 2NaOH(aq) + CuSO4(aq) -------------> Cu(OH)2(s) + Na2SO4(aq)

b) Ca(OH)2(aq) + CO2(g) --------------> CaCO3 + H2O (this is already balanced)

c) Pb(NO3)2 + H2SO4 --------> PbSO4 + 2HNO3.

d) 2KNO3 ------> 2KNO2 + O2

e) H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O)

f) Ca(NO3)2(aq) + (NH4)2CO3(aq) ----------------> CaCO3(s) + 2NH4NO3(aq)

3 0

3 years ago

Read 2 more answers

How many moles of hydrogen are in 3. 06 × 10⁻³ g of glycine , c₂h₅no₂?.

Gala2k [10]

Answer:

n = 6.06 x $10^{-4}$ mol

Explanation:

n =?

m = 3.06 x 10-³ g

M (H5) = 5 x 1.01 (Since we only want hydrogen)

Atomic mass of C = 12.01

Atomic mass of H is 1,01, etc.

Having this data, we can use the Molar mass formula and change it so we can know the quantity of matter (n) in moles, and we just replace it.

M = $\frac{m}{n}$ ⇔ n = $\frac{m}{M}$ ⇔ n = $\frac{3.06 x 10^{-3} }{5,05}$ ⇔ n = 6.06 x $10^{-4}$ mol

Note: The numbers I've used may be different from yours, by a small difference. I don't know if it's the case, but hope it helped.

8 0

2 years ago