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Sedbober [7]
3 years ago
7

How many grams would 3.98 x 10^24 atoms of oxygen weigh

Chemistry
2 answers:
siniylev [52]3 years ago
8 0

Answer:

105.75 grams

Explanation:

(3.98 x 10^24 oxygen atoms) / (6.022 x 10^23 oxygen atoms * mol^-1) = 6.61 mol^-1

(6.61 mol^-1)(16.00 g*mol^-1) = 105.75 g

Semenov [28]3 years ago
4 0

Answer:

a little bit

Explanation:

i think

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What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
uysha [10]
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
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3 years ago
What is the pressure in a 5.00 L tank with<br> 7.10 moles of oxygen at 39.3 °C?
Katena32 [7]

Answer:

36.4 atm

Explanation:

To find the pressure, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = ? atm                         R = 0.0821 L*atm/mol*K

V = 5.00 L                       T = 393 °C + 273.15 = 312.45 K

n = 7.10 moles

PV = nRT

P(5.00 L) = (7.10 moles)(0.0821 L*atm/mol*K)(312.45 K)

P(5.00 L) = 182.130

P = 36.4 atm

8 0
1 year ago
Write the equilibrium expression for N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) + heat I have no idea where to even start, due to the corona
motikmotik

Answer:

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium

N_2 (g) + 3 H_2 (g)\rightleftharpoons 2 NH_3 (g) + heat

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

5 0
2 years ago
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