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Ahat [919]
3 years ago
14

What is always true of an object with a lit of mass ?

Chemistry
2 answers:
yawa3891 [41]3 years ago
4 0
A greater force is required
sertanlavr [38]3 years ago
3 0

Such an object makes a larger dent in the fabric of space-time than an object with little mass. (It has a greater gravitational attraction than less massive objects)

A greater force is required to accelerate such an object than a less massive object

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Which of the following best describes an atom?
Tanzania [10]

Answer: The smallest unit of matter.

Explanation:

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4 years ago
Approximately how many ice cubes must melt to cool 650 milliliters of water from 29°C to 0°C? Assume that each ice cube contains
qwelly [4]

Answer : The number of ice cubes melt must be, 13

Explanation :

First we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

Density of water = 1.00 g/mL

Volume of water = 650 mL

\text{Mass of water}=1.00g/mL\times 650mL=650g

Now we have to calculate the heat released on cooling.

Heat released on cooling = m\times c\times (T_2-T_1)

where,

m = mass of water = 650 g

c = specific heat capacity of water = 4.18J/g^oC

T_2 = final temperature = 29^oC

T_2 = initial temperature = 0^oC

Now put all the given values in the above expression, we get:

Heat released on cooling = 650g\times 4.18J/g^oC\times (29-0)^oC

Heat released on cooling = 78793 J = 78.793 kJ   (1 J = 0.001 kJ)

As, 1 ice cube contains 1 mole of water.

The heat required for 1 ice cube to melt = 6.02 kJ

Now we have to calculate the number of ice cubes melted.

Number of ice cubes melted = \frac{\text{Total heat}}{\text{Heat for 1 ice cube}}

Number of ice cubes melted = \frac{78.793kJ}{6.02kJ}

Number of ice cubes melted = 13.1 ≈ 13

Therefore, the number of ice cubes melt must be, 13

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Explanation:

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36.02g of h2o is produced
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The density of nitric acid (HNO3) is 1.41 g/ml. how many ml are in 20.0g of the nitric acid?
soldi70 [24.7K]

Answer:

14.2

Explanation:

to find mL we must cancel grams we do this by the equation:

20/1.41 = 14.2 mL

7 0
3 years ago
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