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emmainna [20.7K]
3 years ago
5

Eliminating a disease suppose that in any given year, the number of cases of a disease is reduced by 20%. if there are 10,000 ca

ses today, how many years will it take (a) to reduce the number of cases to 1000? (b) to eliminate the disease; that is, to reduce the number of cases to less than 1?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0
A. in 11 years it will be reduced to 858.99, in 10 it will be reduced to 1,073.
b. 43 years
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Find missing variable and check: -3(x-6)+4(x+1)=7x-14
lana66690 [7]

We need to solve the equation to find x

-3(x-6)+4(x+1)=7x-14

We will simplify the left side by multiply each bracket by the number before it

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4(x + 1) = 4(x) + 4(1) = 4x + 4

Now put them on the left side

-3x+18+4x+4=7x-14

Add the like terms on the left side

\begin{gathered} (-3x+4x)+(18+4)=7x-14 \\ x+22=7x-14 \end{gathered}

Now we will collect x on the right side and the numbers on the left side

Subtract x from both sides

\begin{gathered} x-x+22=7x-x-14 \\ 22=6x-14 \end{gathered}

Add 14 to both sides

\begin{gathered} 22+14=6x-14+14 \\ 36=6x \end{gathered}

Divide both sides by 6 to find x

\begin{gathered} \frac{36}{6}=\frac{6x}{6} \\ 6=x \end{gathered}

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3 0
1 year ago
Shawn bought a beautiful house for 350,000. her loan was for 30 years at 6.5% APR. how much money will she
viva [34]

Answer:

D

Step-by-step explanation:

I am not sure if my answer is right, this is what I did :-

350,000 x 30 = 10,500,000

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Tell me if I was right. Thank you !!

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3 years ago
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8 0
3 years ago
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