Question

Find the coordinates of point P witch cuts line segment AB into two parts with a ratio of 3:8

Answer 1

Answer:

Step-by-step explanation:

So we'll take the ratio of  3:8  to mean  3 to 8   ,  which is 11 total parts.

since we know that part, and we can see that the x coordinate goes from -15 to 7, which is a total  of 22  and that y goes from 18 to 7, which is a total of 11 then we know that  we can just break up each into their 3:8 ratios

3:8=11 for the y component

6:16=22 for the x component

so subtract 3 from the B point for the y or add 3 to the A point , either works here,   Let's go from B so y = 10 (7+3)  and x = 1  (7-6)

So a point at (1,10) will be on the line and at a ratio of 3:8  :)