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kotegsom [21]
3 years ago
10

The following image represent a potential garden space in a section of a yard. If chicken wire comes in rolls that are 48 inches

long, determine the smallest amount of rolls that will be needed to fence the garden

Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

7 rolls

Step-by-step explanation:

Arc length

l = (130/360) * 2π(6)

l = 13.6135681656

Side lengths

there are (2) 6 ft radii

l = 12

-------------------

total perimeter

12 + 13.6

25.6 feet

----------------

rolls needed

48in = 4ft

25.6 / 4 = 6.4

Round up as full rolls must be bought

7 rolls

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
When I evaluate m=2 , h=1 then what would mh+3 would be?
Andrei [34K]

Answer:5

Step-by-step explanation: since you know that m=2, and h=1, mh is the same as m × h, or 2×1. Which is equal to 2, you then add 3 to get your answer

7 0
3 years ago
PLEASE HELP! I AM BEING TIMED!!<br> will give you brainliest!!!
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5 0
3 years ago
Will give brainliest if answer is correct.
Pachacha [2.7K]

Answer:

Length = 13

Width = 7

Step-by-step explanation:

Given:

length = 2(width) - 1

Area of a Rectangle = lω = 91 cm²

Calculation:

Area of a Rectangle = lω = 91 cm²

(2ω-1)ω = 91

= 2ω²- ω - 91 = 0

=(2ω+13)(ω-7)=0

ω = -6.5       ω=7

length = 2(width) - 1

l=2(7) - 1

l = 13

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