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3 years ago

10

The following image represent a potential garden space in a section of a yard. If chicken wire comes in rolls that are 48 inches

long, determine the smallest amount of rolls that will be needed to fence the garden

1 answer:

Alinara [238K]3 years ago

4 0

Answer:

7 rolls

Step-by-step explanation:

Arc length

l = (130/360) * 2π(6)

l = 13.6135681656

Side lengths

there are (2) 6 ft radii

l = 12

-------------------

total perimeter

12 + 13.6

25.6 feet

----------------

rolls needed

48in = 4ft

25.6 / 4 = 6.4

Round up as full rolls must be bought

7 rolls

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The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

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3 years ago

When I evaluate m=2 , h=1 then what would mh+3 would be?

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3 years ago

PLEASE HELP! I AM BEING TIMED!!<br> will give you brainliest!!!

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3 years ago

Will give brainliest if answer is correct.

Pachacha [2.7K]

Answer:

Length = 13

Width = 7

Step-by-step explanation:

Given:

length = 2(width) - 1

Area of a Rectangle = lω = 91 cm²

Calculation:

Area of a Rectangle = lω = 91 cm²

(2ω-1)ω = 91

= 2ω²- ω - 91 = 0

=(2ω+13)(ω-7)=0

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