The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches
So, length of sides will be,
The answer is B.) F and I
Negative times a Negative = Positive
Positive times a Positive = Positive
Negative times a Positive = Negative
Positive times a Negative = Negative
Option A:
Negative * Positive * Negative * Positive
Negative * Negative * Positive
Positive * Positive
Positive
Option B:
Anything times 0 is 0, this is incorrect.
Option C:
Negative * Negative * Negative * Negative
Positive * Negative * Negative
Negative * Negative
Positive
Option D:
Negative * Positive * Negative * Negative
Negative * Negative * Negative
Positive * Negative
Negative
Therefore your answer is D.
Answer:
65
Step-by-step explanation:
the square means 90 add that to 25 and subtract from 180
Answer:
Step-by-step explanation:
Given
(a)distance
speed=1.2 m/s
=64.6 at 3.53 m/s
total time 
=53.83+18.3=72.13 s
Average velocity
(b)total distance
Average velocity
