All categories

3 years ago

Can someone help me please will give BRAINIEST

Chemistry

2 answers:

Misha Larkins [42]3 years ago

8 0

55.3C= 328.45K
255K= -18.5C
447K= 174.85C
-14C= 259.15K

patriot [66]3 years ago

8 0

Answer:

55.3 = 328.45k

255 = 18.15°c

447 = 173.85°c

-14 = 14k

You might be interested in

Does phosphate have the ability to conduct electricity?

baherus [9]

Answer:

Red phosphorous can vary in colour from orange to purple, due to slight variations in its chemical structure. The third form, black phosphorous, is made under high pressure, looks like graphite and, like graphite, has the ability to conduct electricity.

Explanation:

4 0

3 years ago

How many grams of H3PO4 are in 300 mL of a .50 M solution of H3PO4

Liono4ka [1.6K]

The first thing you need to do is convert mL into L
so (175 mL)(.001L/1mL)=.175L then you multiply by the Molarity of H3PO4 which is 3.5mol/L so (.175L)(3.5mol/L)=.6125 mol H3PO4, and since it wants the answer in grams you then multiply (.6125molH3PO4) by the molar mass of H3P04 which is about 97.99g and your answer is 60.02g which is about 60 grams of H3PO4. Hope this helped

3 0

4 years ago

A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?

Elodia [21]

Answer: The mole fraction of barium chloride in the solution is 0.024

Explanation:

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

To calculate the mass of solution, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

$1.230g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.230g/mL\times 1000mL)=1230g$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

$1.30mol=\frac{\text{Mass of barium chloride}}{208g/mol}\\\\\text{Mass of barium chloride}=(1.30mol\times 208g/mol)=270.4g$

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

Calculating the moles of water:

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{959.6g}{18g/mol}\\\\\text{Moles of water}=53.31mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For barium chloride:

$\chi_{\text{(barium chloride)}}=\frac{n_{\text{(barium chloride)}}}{n_{\text{(water)}}+n_{\text{(barium chloride)}}}$

$\chi_{\text{(barium chloride)}}=\frac{1.30}{1.30+53.31}\\\\\chi_{\text{(barium chloride)}}=0.024$

Hence, the mole fraction of barium chloride in the solution is 0.024

6 0

4 years ago

What is an example of a scope three carbon emission?

MAXImum [283]

Production of materials and transportation are the examples of three carbon emission.

Extraction and production of purchased materials and transportation of purchased fuels are the examples of three carbon emission. Scope 3 emissions refers to all indirect emissions that occur in the chain of the reporting company that is included in both upstream and downstream emissions.

Big machineries are used for the production and extraction of materials as well as the transportation requires fossil fuels for working which releases carbondioxide gas in the atmosphere so we can conclude that production of materials and transportation are the examples of three carbon emission.

5 0

3 years ago

A solution of HCl gas dissolved in water (sold commercially as "muriatic acid," a solution used to clean masonry surfaces) has 2

disa [49]

Answer:

[HCl] = 6.09 M

Xm HCl = 0.11

Explanation:

Let's analyse data:

20.22 g of solute / 100 g of solution

Solution's density = 1.10 g/mL

As we have the mass of solution and its density we determine solution's volume to stablish [M]

Density = Mass / volume → 1.10 g/mL = 100 g / Volume

100 g / 1.10g/mL = 90.9 mL

Let's convert the volume to L → 90.9 mL . 1L/ 1000mL = 0.0909L

We convert the mass of solute to moles → 20.22 g . 1mol/ 36.45g =

0.554 moles

[M] = Molarity (moles of solute /1L of solution) = 0.554 mol/0.0909L = 6.09M

Mole fraction (Xm) = Moles of solute / Total moles

Total moles = Moles of solute + Moles of solvent

Mass of solvent = Mass of solution - Mass of solute

Mass of solvent = 100 g - 20.22 g = 79.78g

We convert the mass to moles → 79.78 g / 18g/mol = 4.43 moles

Total moles = 4.43 moles + 0.554moles = 4.984 moles

Xm = 0.554 / 4.984 = 0.11

6 0

3 years ago