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sladkih [1.3K]
3 years ago
5

Identify the molecules with a dipole moment: (a) SF (b) CF (c) CCCB (d) CHCI (e) H.CO

Chemistry
1 answer:
trapecia [35]3 years ago
6 0

Answer: An atom has either tendency of accepting or losing electron, on the basis of this virtue it is named as

  • Electronegative: An atom has tendency to attract the shared pair of electron towards itself is called electronegative.
  • Electropositive: An atom that has tendency to give the shared pair of electron towards an electronegative atom is called electropositive.

For the existence of dipole within a molecule there must be a difference in electronegativity of the atoms participating in it. All the molecules here have dipole moment because the atoms participating in them have a difference in electronegative.

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5 0
3 years ago
The united stated chemical industry produces more sulfuric acid, in terms of mass, than any other chemical. What is the mass of
Dahasolnce [82]

Answer:

318.749g

Explanation:

The find the mass,

We use this formula

Number of mole = mass/ molar mass

Since number of mole = 3.25mol

Let the number of mass be x

The molar mass of H2SO4

H - 1.00784 * 2= 2.01568

S - 32.065

O - 15.999 * 4 = 63.996

Note there are 2 moles of H and 4 moles of O and 1 mole of S

Molar mass of H2SO4 = 2.01568 + 32.065 + 63.996

= 98.07668g/mol

Number of mole= 3.25mol

3.25 = x / 98.07668

x = 3.25 * 98.07668

x= 318.749g

Hence, the number of mass is 318.749g

Hope it will help you.

7 0
3 years ago
Read 2 more answers
Place the parts of the human circulatory system in order from highest to lowest degree of internal organization.
Softa [21]

Answer:

cell tissue organ and system

8 0
2 years ago
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Which of the gas laws takes into account the forces of attraction between molecules based on the characteristics of the gas? *
Alika [10]
The answer is Boyle’s Law
5 0
3 years ago
A 1.00 cm2 blackbody surface emits 201 watts of radiant power. What is the temperature of the surface? Give to the nearest whole
erastovalidia [21]

Explanation:

Formula for black body radiation is as follows.

                 \frac{P}{A} = \sigma \times T^{4} J/m^{2}s

where,       P = power emitted

                 A = surface area of black body

          \sigma = Stephen's constant = 5.6703 \times 10^{-8} watt/m^{2}.K^{-4}

As area is given as 1.0 cm^{2}. Converting it into meters as follows.

           1.00 cm^{2} \times \frac{(10^{-2})^{2} m^{2}}{1 cm^{2}}      (as 1 m = 100 cm)

            = 1 \times 10^{-4} m^{2}

It is given that P = 201 watts. Hence,  

       \frac{201 watts}{1 \times 10^{-4} m^{2}} = 5.6703 \times 10^{-8} watt/m^{2}.K^{-4} \times T^{4}

                T^{4} = 35.45 \times 10^{12}

                       T = (35.45 \times 10^{12})^{1/4}

                          = 8862.5 K

Thus, we can conclude that the temperature of the surface is 8862.5 K.

7 0
3 years ago
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