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ahrayia [7]
3 years ago
5

When a warm air mass and a cold air masses meet but they push at each other and neither one can move (at a stand off) it’s calle

d a?
Chemistry
1 answer:
Tom [10]3 years ago
8 0
This is called a Cold Front.
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Is the tendency of copper to turn green when exposed to air chemical or physical property?
Zielflug [23.3K]
<u>Chemical</u>. The copper atoms form new chemical bonds with atoms in the air.
8 0
2 years ago
A block of metal has a volume of 14.0in3 and weighs 5.16 lb .
riadik2000 [5.3K]

The density of metal block in grams per cubic centimeter is 10.70 g/cm³.

Given,

Mass of metal block = 5.16 lb  

1 lb = 453.592 g

5.26 lb = 2340.536 g

The volume of metal block = 14 in 3

1 in = 2.5 cm

1 in 3 = 15.625 cm³

14 in 3 = 218.75 cm³

Density is defined as the mass per unit volume of a substance. Or, it is the ratio of mass to the volume of the substance.

As we know,

Density = mass/volume

Or, density = 2340.536 / 218.75

Or, density = 10.70 g/cm³

Therefore, the density of the metal block is 10.70 g/cm³.

To learn more about the density, visit: brainly.com/question/15164682

#SPJ9

5 0
2 years ago
PLEASE HELP CHEMITRY!
Delicious77 [7]

Answer:

.

Explanation:

5 0
2 years ago
A gas system has an initial number of moles of 0.693 moles with the volume unknown. When the number of moles changes to 0.928 mo
lara [203]

Answer:

The initial volume in mL is 5959.2 mL

Explanation:

As the number of moles of a gas increases, the volume also increases.  Hence, number of moles and volumes are directly proportional i.e

n ∝ V

Where n is the number of moles and V is the volume

Then, n = cV

c is the proportionality constant

∴n/V = c

Hence n₁/V₁ = n₂/V₂

Where n₁ is the initial number of moles

V₁ is the initial volume

n₂ is the final number of moles

and V₂ is the final volume.

From the question,

n₁ = 0.693 moles

V₁ = ?

n₂ = 0.928 moles

V₂ = 7.98 L

Putting the values into the equation

n₁/V₁ = n₂/V₂

0.693 / V₁ = 0.928 / 7.98

Cross multiply

∴ 0.928V₁ = 0.693 × 7.98  

0.928V₁ = 5.53014

V₁ = 5.53014/0.928

V₁ = 5.9592 L

To convert to mL, multiply by 1000

∴ V₁ = 5.9592 × 1000 mL

V₁ = 5959.2 mL

Hence, the initial volume in mL is 5959.2 mL

5 0
2 years ago
1. Name the compound present in a sample of dry air.
aev [14]

Answer:

not air

Explanation:

I think so

hahaha

7 0
2 years ago
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