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4 years ago

5

When a warm air mass and a cold air masses meet but they push at each other and neither one can move (at a stand off) it’s calle

d a?

1 answer:

Tom [10]4 years ago

8 0

This is called a Cold Front.

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The reaction of ethyl acetate with sodium hydroxide, CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) is first order in CH3COOC2H

Ne4ueva [31]

Answer:

so the reaction rate increases by a factor 6.

Explanation:

For the given equation the reaction is first order with respect to both ester and sodium hydroxide

So we can say that the rate law is

$Rate(initial)=K[NaOH][CH_{3}COOC_{2}H_{5}]$

now as per given conditions the concentration of ester is increased by half it means that the new concentration is 1.5 times of old concentration

The concentration of NaOH is quadrupled means the new concentration is 4 times of old concentration.

The new rate law is

$Rate(final)=K[1.5XNaOH][4XCH_{3}COOC_{2}H_{5}]$

the final rate = 6 X initial rate

so the reaction rate increases by a factor 6.

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4 years ago

In the teapot dome scandal, what did the secretary of the interior albert fall lease

yuradex [85]

Albert Fall secretly leased federal oil reserves for personal gain.

7 0

3 years ago

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Methane, CH4, burns in oxygen gas to form water and carbon dioxide.

Lemur [1.5K]

$ch4 + 202 2h20 + co2$

CH4 + 2O2 --> 2H2O +CO2

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3 years ago

When rubidium ions are heated to a high temperature, two lines are observed in its line spectrum at wavelengths (a) 7.9 × 10−7 m

svetlana [45]

Answer:

The frequencies of the two lines are:

a) $3.79\times 10^{14} s^{-1}$

b) $7.14\times 10^{14} s^{-1}$

When we heat rubidium compound we will see red color.

Explanation:

$\nu=\frac{c}{\lambda }$

c = speed of light

$\lambda$ = wavelength of light

a) Frequency of the light when wavelength is equal to $7.9\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{7.9\times 10^{-7}}$

$\nu=3.79\times 10^{14} s^{-1}$

This frequency corresponds to red light

b) Frequency of the light when wavelength is equal to $4.2\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{4.2\times 10^{-7}}$

$\nu=7.14\times 10^{14} s^{-1}$

This frequency corresponds to violet light

When we heat rubidium compound we will see red color.

4 0

3 years ago

PLEASE HELP ASAP!!!

solong [7]

The answer is, C: both Erin and Chris are correct.

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4 years ago

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