Answer:
The ratio of Tan B is
![\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}](https://tex.z-dn.net/?f=%5Ctan%20B%3D%20%5Cdfrac%7BAC%7D%7BBC%7D%3D%5Cdfrac%7B8%7D%7B15%7D)
OR
![\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}](https://tex.z-dn.net/?f=%5Ctan%20A%3D%20%5Cdfrac%7BBC%7D%7BAC%7D%3D%5Cdfrac%7B15%7D%7B8%7D)
Step-by-step explanation:
In Right Angle Triangle ABC
angle C = 90°
AB = Ramp = 17 feet
BC =Horizontal distance = 15 feet
AC = Height from floor = 8 feet
To Find:
Ratio of Tan B = ?
Solution:
In Right Angle Triangle ABC By Tangent Identity we have
![\tan B= \dfrac{\textrm{side opposite to angle B}}{\textrm{side adjacent to angle B}}](https://tex.z-dn.net/?f=%5Ctan%20B%3D%20%5Cdfrac%7B%5Ctextrm%7Bside%20opposite%20to%20angle%20B%7D%7D%7B%5Ctextrm%7Bside%20adjacent%20to%20angle%20B%7D%7D)
Substituting the given values we get
![\tan B= \dfrac{AC}{BC}=\dfrac{8}{15}](https://tex.z-dn.net/?f=%5Ctan%20B%3D%20%5Cdfrac%7BAC%7D%7BBC%7D%3D%5Cdfrac%7B8%7D%7B15%7D)
OR
![\tan A= \dfrac{BC}{AC}=\dfrac{15}{8}](https://tex.z-dn.net/?f=%5Ctan%20A%3D%20%5Cdfrac%7BBC%7D%7BAC%7D%3D%5Cdfrac%7B15%7D%7B8%7D)
Answer:
![E=5.76\times 10^{-8}N/C](https://tex.z-dn.net/?f=E%3D5.76%5Ctimes%2010%5E%7B-8%7DN%2FC)
Step-by-step explanation:
We are given that
Charge of atomic nucleus,q=+40 e=![40\times 1.6\times 10^{-19}C](https://tex.z-dn.net/?f=40%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7DC)
Because
1 e=![1.6\times 10^{-19} C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%20C)
Charge of atomic nucleus=![64\times 10^{-19}C](https://tex.z-dn.net/?f=64%5Ctimes%2010%5E%7B-19%7DC)
Distance of charge form the center of nucleus=r=1 m
We have to find the magnitude of electric field at distance r
![E=\frac{Kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BKq%7D%7Br%5E2%7D)
Where K=![9\times 10^9Nm^2/C^2](https://tex.z-dn.net/?f=9%5Ctimes%2010%5E9Nm%5E2%2FC%5E2)
Using the formula
![E=\frac{9\times 10^9\times 64\times 10^{-19}}{1}=576\times 10^{-10}N/C](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B9%5Ctimes%2010%5E9%5Ctimes%2064%5Ctimes%2010%5E%7B-19%7D%7D%7B1%7D%3D576%5Ctimes%2010%5E%7B-10%7DN%2FC)
![E=\frac{576}{100}\times 10^2\times 10^{-10}=5.76\times 10^{2-10}=5.76\times 10^{-8}N/C](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B576%7D%7B100%7D%5Ctimes%2010%5E2%5Ctimes%2010%5E%7B-10%7D%3D5.76%5Ctimes%2010%5E%7B2-10%7D%3D5.76%5Ctimes%2010%5E%7B-8%7DN%2FC)
Using identity![a^x\cdot a^y=a^{x+y}](https://tex.z-dn.net/?f=a%5Ex%5Ccdot%20a%5Ey%3Da%5E%7Bx%2By%7D)
Hence, the magnitude of electric field=![E=5.76\times 10^{-8}N/C](https://tex.z-dn.net/?f=E%3D5.76%5Ctimes%2010%5E%7B-8%7DN%2FC)
Answer:
2/5
Step-by-step explanation:
The formula for slope is
m = (y2-y1)/(x2-x1)
= (5-7)/(1-6)
=-2/-5
=2/5