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frosja888 [35]
3 years ago
7

Find the area of the figure. Round to the nearest tenth if necessary.

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
So I went ahead and divided up the figure so that you would understand what I'm going to tell you. Let's start with the red rectangle.

The distance from point R to point I is 6 units and the distance from Point R to point S is 5 units. 6*5 = 30 so that red rectangle has an area of 30 units

Now let's calculate triangle AVI. Area of a triangle is Base * Height. The base is 1 and the height is 5 which means the area of triangle AVI is 5.

Next, triangle ALT. From Point A to point L is 4 unit. From Point L to point T is 3 units. 4*3 is 12. So triangle ALT has an area of 12.

Triangle TSI. From Point T to point L is 3 units. From Point L to X is 2. Triangle TSI has an area of 6.

Now we add all of them up. 30+5+12+6 = 53. In total, RSTUV has an area of 53

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Job a, $15/hour, job b, $12/hour, how many hours at each job to earn $360
stira [4]

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Job A, will take 24 hours and Job B, will take 30 hours

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Evaluate the expression if a=2,b=-3,C=-1, and D=4<br><br><br> -2(b^2-5c)
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\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • Equivalent value = -28

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \: - 2( {b}^{2}  - 5c)

( put the values )

\qquad❖ \:  \sf \: - 2 \{( - 3) {}^{2}  - 5( - 1) \}

\qquad❖ \:  \sf \: - 2(9 -  (- 5))

\qquad❖ \:  \sf \: - 2(9 + 5)

\qquad❖ \:  \sf \: - 2 \times 14

\qquad❖ \:  \sf \: - 28

\qquad \large \sf {Conclusion}  :

  • -2(b² - 5c) = -28

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and π = pie

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