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kondaur [170]
3 years ago
11

Find the sum of the first five terms of the geometric series 1+3+9+...

Mathematics
2 answers:
Nitella [24]3 years ago
5 0

Good evening ,

Answer:

B. 121

Step-by-step explanation:

1×3=3

3×3=9

9×3=27

27×3=81

the sum = 1+3+9+27+81 = 121.

:)

ryzh [129]3 years ago
3 0

The sum of 1^{st} five terms of the series is 121.

Option - B

<u>SOLUTION: </u>

Given that, we have to find the sum of the first five terms of the geometric series 1 + 3 + 9 + ...  

We already know, first three terms, let us find next two terms also.

\text { Then, common ratio }=\frac{\text { second term of series }}{\text { first term series }}=\frac{3}{1}=3

Now, we know that, 4^{th} term is 3^{rd} term multiplied by the common ratio so, 4^{\text {th }} \text { term }=9 \times 3 \rightarrow 4^{\text {th }} \text { term }=27

And, 5^{th} term is 4^{th} term multiplied by common ratio. So, 5^{\text {th }} \text { term }=27 \times 3 \rightarrow 5^{\text {th }} \text { term }=81

Now, sum of first five terms = 1 + 3 + 9 + 27 + 81 = 4 + 36 + 81 = 40 + 81 = 121

Hence, the sum of 1^{st} five terms of the series is 121.

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