Answer:
40.1 g
Explanation:
The <em>balanced equation</em> is:
First we <u>convert 86.5 g of calcium chlorate into moles</u>, using its<em> molar mass</em>:
- 86.5 g Ca(ClO₃)₂ ÷ 206.98 g/mol = 0.418 mol Ca(ClO₃)₂
Then we <u>convert Ca(ClO₃)₂ moles into O₂ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:
- 0.418 mol Ca(ClO₃)₂ *
= 1.254 mol O₂
Finally we <u>convert O₂ moles into grams</u>:
- 1.25 mol O₂ * 32 g/mol = 40.1 g O₂
Answer:
Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:
Volume = 60.0 g ( 1 mL / 0.70 g ) = 85.71 mL
Therefore, the correct answer is option B.
Explanation:
Answer:
When the kinetic energy of water vapor decreases during condensation, <u>slowly moving particles near the cool surface condense.</u>
Explanation:
The change of state from a gas to a liquid is condensation. Liquid molecules which have this certain kinetic energy threshold escape from the surface and become vapor. As a result, the remaining liquid molecules now have lower kinetic energy. The temperature of the remaining liquid decreases as evaporation occurs.
The air that surrounded it cooled the cold can or glass. When you're cooling off .They lose kinetic energy, a gas. The particles move more slowly as they move, the attractions between them cause the formation of droplets of liquid. Condensed With, when hot air containing water vapor reaches water, water also forms. Cold surface touch, such as a glass of ice or soil that has a cold surface refrigerated throughout the night.
Answer:
18.066 x 10^23 atoms of Au
Explanation:
ONE mole = 6.022 x 10^23 particles
3 x 6.022 x 10^23
Answer:
a. If the reaction mixture initially contains only OF2(g), then at equilibrium, the reaction mixture will consist of essentially only O2(g) and F2(g).
Explanation:
The answer is a) because the value for Kp is really close to zero (having x10⁻¹⁵), this means that at equilibrium O₂ and F₂ will be significantly more present than OF₂.
