Volume is a three-dimensional scalar quantity. The volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Since an inch is equal to 1/12 of a foot. Therefore, the thickness of the pool deck is,
3 inches = 0.25 foot
If a pool deck of 650 square feet is to be laid with concrete 3" thick, then the volume of concrete that will be needed is,
Volume of concrete = 650 ft² × 0.25 ft = 162.5 ft³
Now, one yard is equal to 3 feet, therefore,
1 cubic foot = 1/27 cubic yards
162.5 cubic feet = 6.0185 cubic yards
Hence, the volume of concrete that will have to be poured into the pool deck is 6.0185 cubic yards.
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Given:

x lies in the III quadrant.
To find:
The values of
.
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,




x lies in the III quadrant. So,


Now,



And,





We know that,



Therefore, the required values are
.
If you mean in decimal form then it would be 15.65
The correct answer is C (7, 9)
Firstly we know that each point is 6 away from the other in terms of x and in terms of y. Now we also know that for every 6, we will be one away from point B and five away from point A. We know this because the ratio is AB 5:1, meaning that the 5 is on the A side (they both come first).
So, we can just add 5 to each of the A value numbers to get point P.
A = (2, 4)
P = (2+5, 4+5)
P = (7, 9)
Answer:
<h2>Midpoint (1 , 5)</h2>
Step-by-step explanation:
Let (x , y) be the coordinates of the midpoint then:
