keeping in mind that radius is half the diameter, we know this cone has a diameter of 2 inches, so it has a radius of 1 inch, kinda small really for ice-cream, but anyhow.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1\\ h=6 \end{cases}\implies V=\cfrac{\pi (1)^26}{3}\implies V=2\pi \implies \underset{\textit{rounded up}}{V\approx 6}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%5C%5C%20h%3D6%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%281%29%5E26%7D%7B3%7D%5Cimplies%20V%3D2%5Cpi%20%5Cimplies%20%5Cunderset%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%5Capprox%206%7D)
For 1.
Solution,
Sides(l)= 3.5
Now,
Perimeter of square=4l
=4*3.5
=14
Then,
Area of square =l^2
=3.5*3.5
=12.25
For 2.
Solution,
Sides(l)=1
Now, perimeter of square =4l
=4*1
=4
Then,
Area of square =l^2
=1*1
=1
For 3.
Solution,
Sides(l)= 20
Now,
Perimeter of square=4l
=4*20
=80
Then,
Area of square =l^2
=20*20
=400
Answer:
n + n+2 + m+4 = 87
I got this answer.....hope it may helpful
<span>let us say we assume the number 550 is 100%- because the out put value of the task is two make sense.</span>
The same as the second answer as the word congruent means to be identical so using this we can infer it’s the same as e I think