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galina1969 [7]
3 years ago
6

Use square roots to solve the equation x^2 = −25 over the complex numbers. Enter your answers in numerical order.

Mathematics
2 answers:
Mrrafil [7]3 years ago
6 0

Answer:

The answer is 5

Step-by-step explanation:

x^2= -25

x=√-25

x=5

bija089 [108]3 years ago
3 0

Answer:

Step-by-step explanation:

x^2= -25

x=5i and -5i

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Use integration by parts to find the integrals in Exercise.<br> ∫^3_0 3-x/3e^x dx.
Viefleur [7K]

Answer:

8.733046.

Step-by-step explanation:

We have been given a definite integral \int _0^3\:3-\frac{x}{3e^x}dx. We are asked to find the value of the given integral using integration by parts.

Using sum rule of integrals, we will get:

\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx

We will use Integration by parts formula to solve our given problem.

\int\ vdv=uv-\int\ vdu

Let u=x and v'=\frac{1}{e^x}.

Now, we need to find du and v using these values as shown below:

\frac{du}{dx}=\frac{d}{dx}(x)

\frac{du}{dx}=1

du=1dx

du=dx

v'=\frac{1}{e^x}

v=-\frac{1}{e^x}

Substituting our given values in integration by parts formula, we will get:

\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(x*(-\frac{1}{e^x})-\int _0^3(-\frac{1}{e^x})dx)

\frac{1}{3}\int _0^3\frac{x}{e^x}dx=\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))

\int _0^3\:3dx-\int _0^3\frac{x}{3e^x}dx=3x-\frac{1}{3}(-\frac{x}{e^x}- (\frac{1}{e^x}))

Compute the boundaries:

3(3)-\frac{1}{3}(-\frac{3}{e^3}- (\frac{1}{e^3}))=9+\frac{4}{3e^3}=9.06638

3(0)-\frac{1}{3}(-\frac{0}{e^0}- (\frac{1}{e^0}))=0-(-\frac{1}{3})=\frac{1}{3}

9.06638-\frac{1}{3}=8.733046

Therefore, the value of the given integral would be 8.733046.

6 0
3 years ago
Together, Matthew and Daniel have 67 DVDs. Matthew's collection has 3 times as many DVDs as Daniel's collection. Write an algebr
ryzh [129]
<h3>Answer: 3x + x = 67</h3><h3>To solve: 4x = 67</h3><h3>                  /4.   /4</h3><h3>x = 16.75</h3><h3></h3>
8 0
3 years ago
Han buys an item with a normal price of $15.
KiRa [710]

Answer:

$1.50

Step-by-step explanation:

15*.10=1.50

4 0
3 years ago
Initially, there were equal amount of roses and tulips at a store. Each bouquet was made with 3 roses and 4 tulips. After the bo
egoroff_w [7]

Answer:

12 bouquets

Step-by-step explanation:

Let there be x number of roses and x number of tulips initially at the store.  Each bouquet was made with 3 roses and 4 tulips. Assume that y bouquets were made in total.

If each bouquet was made with 3 roses and 4 tulips, then y bouquets will be made with 3y roses and 4y tulips.

After the bouquets were all made, there were 30 roses and 18 tulips left in the store. This means, if we subtract number of roses that were used in bouquets from total number of roses, the result must be 30. Likewise, for tulips the result would be 18. This can be represented as:

x - 3y = 30                               Equation 1

x  - 4y = 18                                Equation 2

Subtracting Equation 2 from Equation 1, we get:

x - 3y - (x - 4y) = 30 - 18

x - 3y - x + 4y = 12

y = 12

Since y represents the number of bouquets made, we can conclude that 12 bouquets were made in the store.

5 0
3 years ago
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The spoke of a wheel reaches from the center of the wheel to its rim. If the circumference of the rim of the wheel is 48 inches,
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Check the picture below

4 0
3 years ago
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