The answer for this would be "B".
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Answer:
ok
Explanation:
what is the length of the court. you need the length to answer the question
Correct Answer: B optionPotential Difference = V = 200 V
Charge on the plate = Q =
![5.0*10^{-9}](https://tex.z-dn.net/?f=5.0%2A10%5E%7B-9%7D%20)
C
Capacitance = C
Q, C and V for a parallel plate capacitor are related as:
Q = CV
⇒
C = Q/V
Using the values in the formula, we get:
![C= \frac{5*10^{-9} }{200}=2.5*10^{-11}](https://tex.z-dn.net/?f=C%3D%20%5Cfrac%7B5%2A10%5E%7B-9%7D%20%7D%7B200%7D%3D2.5%2A10%5E%7B-11%7D%20%20)
F
Therefore, B option is the correct answer.