All categories

2 years ago

A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?

Physics

1 answer:

7nadin3 [17]2 years ago

3 0

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

$v_y=v\ sin(25)$

$v_y=22\ m/s\times\ sin(25)$

$v_y=9.29\ m/s$

Hence, the vertical component of the velocity is 9.29 m/s

You might be interested in

In water, acids form _____.

Amiraneli [1.4K]

The answer is hydrogen ions

8 0

2 years ago

Read 2 more answers

The law of repulsion by Coulomb agrees with:

r-ruslan [8.4K]

<span>In Coulomb's law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. ... Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges</span>

8 0

3 years ago

Read 2 more answers

If you ignore air resistance after an initial force launches a projectile, name all forces acting on it as it moves through the

alekssr [168]

Answer:

Neglecting air resistance, the only force acting on a projectile is gravity.

This force causes the object to accelerate.

Explanation:

As a projectile moves upward, there is a downward force and a downward acceleration due to force of gravity. That is, as the object is moving upward, force of gravity acting on the projectile is causing a steady slowing down of the projectile.

Hence, Gravity is the downward force upon a projectile that influences its vertical motion and causes the parabolic trajectory that is characteristic of projectiles.

From Newton's law of motion, it suggest that force is required to cause an acceleration and not motion. Therefore, force of gravity causes the object to accelerate downwards.

8 0

2 years ago

Two physics students are arguing about superconductors and their discovery, Jeffe says that he can use a

Liono4ka [1.6K]

Answer:

B on edge2020-2021

Explanation:

5 0

2 years ago

Approximately what is the smallest detail observable with a microscope that uses ultraviolet light of frequency 1. 72 x 1015 hz?

postnew [5]

The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light , is calculated as follows: 3× $10^{8}$ / 1.72× $10^{15}$ or approximately 1.74× $10^{-7}$ m.

The distance between the two positive, two negative, or two minimal points on the waveform is known as the wavelength of the wave. The following formula expresses the relationship between the frequency and wavelength of light:

f = c / λ

where, f = frequency of light

c = speed of light

λ = wavelength of light

Given data = f = 1.72× $10^{15}$ Hz

Therefore, λ = 3× $10^{8}$ / 1.72× $10^{15}$

λ = 1.74× $10^{-7}$ m

The wavelength, which represents the size of the smallest detectable detail that uses ultraviolet light , is calculated as follows: 3× $10^{8}$ / 1.72× $10^{15}$ or approximately 1.74× $10^{-7}$ m.

Learn more about light here;

brainly.com/question/15200315

#SPJ4

7 0

1 year ago