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3 years ago

Celera

Physics

1 answer:

Korolek [52]3 years ago

4 0

Hi there!

We know that the MAXIMUM static friction force to be overcome is:

Fs (Force of Static Friction) = μN (Normal Force)

The normal force is equal to the weight of the block AND the vertical component of the applied force, so:

N = Mg + Fasinθ

Plug in the given values:

N = 26.8(9.81) + (89.2)sin(38) = 317.825 N

Multiply by the force of static friction to derive the static force:

0.74 * 317.825 = 325.191 N <-- MAXIMUM STATIC FRICTION FORCE

The force applied, if not greater than this value, will result in an EQUAL and OPPOSITE static frictional force. Thus:

Fs = Horizontal component of the applied force

Fs = 89.2cos(38) = 70.291 N

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