At which point would most of the pendulum's potential energy have been transformed into kinetic energy?

A speck of dust with mass 12 mg and electric charge 10 μC is released from rest in a uniform electric field of magnitude 850 N/C

Marta_Voda [28]

Answer:

$a=708.3m/s^2$

Explanation:

The force experimented by a charge q in a uniform electric field E is F=qE.

Newton's 2nd Law tells us that the relation between acceleration a a mass m experiments when a force F is applied to it is F=ma.

Combining these equations we have am=qE, and since we want the acceleration of the speck of dust, we substitute our values:

$a=\frac{qE}{m}=\frac{(10\times10^{-6}C)(850N/C)}{12\times10^{-6}Kg}=708.3m/s^2$

4 0

3 years ago

If you toss a ball vertically upward in a uniformly moving train, it returns to its starting place. Will it do the same if the t

gogolik [260]

Answer:No

Explanation:

No

As the train is accelerating so train velocity will be more as compared to the ball and thus will cover more distance as compared to the ball.

When the ball is thrown upward with some velocity, it also possesses the train velocity at the time of throwing but as time passes velocity of train increases due to acceleration of the train. This causes the ball to fall behind the point of launch.

3 0

3 years ago

A person standing at the edge of a seaside cliff kicks a stone horizontally over the edge with a speed of 18 m/s. The cliff is 5

Fed [463]

Answer:

it would take 3.26 seg for the stone to fall to the water

Explanation:

If we ignore air friction then:

h=h₀ + v₀*t -1/2*g*t²

where

h= coordinates of the stone in the y axis ( height of the stone relative to the surface of the water )

h₀ = initial coordinates of the stone ( height of the cliff relative to the surface of the water = 52 m )

v₀ = initial vertical velocity = 0 ( since the ball is kicked horizontally , has only initial horizontal velocity , and has 0 vertical velocity )

t = time to reach a height h

g = gravity = 9.8 m/s²

since v₀ =0

h= h₀ - 1/2*g*t²

h₀ - h = 1/2*g*t²

t= √[2(h₀ - h)/g]

when the stone hits the ground h=0 ( height=0) , then replacing values

t=√[2(h₀ - h)/g]=√[2(52 m- 0 m )/(9.8m/s²)] = 3.26 seg

t= 3.26 seg

it would take 3.26 seg for the stone to fall to the water

7 0

3 years ago

A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process have protons been add

AlladinOne [14]

Answer: A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process electrons been removed from it.

Explanation:

It is known that for every atom the protons and neutrons reside in the nucleus of the atom. Whereas electrons move outside the nucleus of an atom. As a result, electrons are able to transfer more easily from one substance to another as compared to the protons.

This is because protons are tightly held by the nucleus of an atom. Whereas electrons are mobile in nature and hence, they can easily move.

Therefore, positive charge on the glass develops due to the removal of electrons from it.

thus, we can conclude that in the given process electrons been removed from the glass object.

8 0

3 years ago

A rectangular block floats in pure water with 0.400 in. above the surface and 1.60 in. below the surface. When placed in an aque

labwork [276]

Answer:

specific gravity = 0.8

specific gravity of solution = 2

Explanation:

given data

rectangular block above water = 0.400 in

rectangular block below water = 1.60 in

material floats below water = 0.800 in

solution

first we get here specific gravity of block that is

specific gravity = block vol below ÷ total block vol × specific gravity water ..............1

put here value we get

specific gravity = $\frac{1.60}{1.60+0.400}$ × 1

specific gravity = 0.8

and now we get here specific gravity of solution that is express as

specific gravity of solution = total block vol ÷ block vol below × specific gravity block ........................2

put here value we get

specific gravity of solution = $\frac{1.60+0.400}{0.800}$ × 0.8

specific gravity of solution = 2

6 0

3 years ago