Explanation :
Displacement refers to the distance between the final and the initial position. Hence the displacement of the ball will be the difference between the initial and the final displacement.
Let the initial position be 0.
Final position = 8 cm
So the difference between initial position and final position = 0 – 8 = - 8 cm.
So the billiard ball comes to rest 8.0 cm behind its orbital position.
Metallic bonds are responsible for many properties of metals, such as conductivity. This is because the bonds can shift because valence electrons are held loosely and move freely. That is option C.
<h3>What are metallic bonds?</h3>
Metallic bonds are defined as those bonds that causes the electrostatic attraction between metal cations and delocalized electrons of another metallic substance.
The characteristics of a metallic compound with metallic bonds include the following:
- thermal and electrical conductivity,
The metallic bonds of these metallic atoms gives them conductivity features because the electrons from the outer shells of the metal atoms are delocalised , and are free to move through the whole structure.
Learn more about metals here:
brainly.com/question/4701542
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Work done is when a force is exerted to cause a displacement in a certain object.
the equation for work done ;
work done = force applied * displacement of the object
when the force applied is not in the same direction as that of the displacement of the object then the effect of the force is not its whole value. The force is then applied at an angle to that of the displacement of the object, then the resultant force is the force exerted* cos of the angle between force and displacement, in this instance the angle is 40 °.
the new equation is then;
work done = force cos 40° * displacement
after substitution,
work = 25 N * 0.76 * 50 m
= 957.55 J
round it off
= 9.6 *10² J
the correct answer is B
<span> </span>Most of the stars in the Milky Way will end their lives as white dwarfs
1)
Answer:
Part 1)
H = 30.6 m
Part 2)
t = 2.5 s
Part 3)
t = 2.5 s
Part 4)
![v_f = 24.5 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2024.5%20m%2Fs)
Explanation:
Part 1)
initial speed of the ball upwards
![v_i = 24.5 m/s](https://tex.z-dn.net/?f=v_i%20%3D%2024.5%20m%2Fs)
so maximum height of the ball is given by
![H = \frac{v_i^2}{2g}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7Bv_i%5E2%7D%7B2g%7D)
![H = \frac{24.5^2}{2(9.80)}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B24.5%5E2%7D%7B2%289.80%29%7D)
![H = 30.6 m](https://tex.z-dn.net/?f=H%20%3D%2030.6%20m)
Part 2)
As we know that final speed will be zero at maximum height
so we will have
![v_f - v_i = at](https://tex.z-dn.net/?f=v_f%20-%20v_i%20%3D%20at)
![0 - 24.5 = (-9.8)t](https://tex.z-dn.net/?f=0%20-%2024.5%20%3D%20%28-9.8%29t)
![t = 2.5 s](https://tex.z-dn.net/?f=t%20%3D%202.5%20s)
Part 3)
Since the time of ascent of ball is same as time of decent of the ball
so here ball will same time to hit the ground back
so here it is given as
t = 2.5 s
Part 4)
since the acceleration due to earth will be same during its return path as well as the time of the motion is also same
so here its final speed will be same as that of initial speed
so we have
![v_f = 24.5 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2024.5%20m%2Fs)
2)
Answer:
a = 9.76 m/s/s
Explanation:
As we know that the object is released from rest
so the displacement of the object in vertical direction is given as
![y = \frac{1}{2}at^2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2)
![4.88 = \frac{1}{2}a(1^2)](https://tex.z-dn.net/?f=4.88%20%3D%20%5Cfrac%7B1%7D%7B2%7Da%281%5E2%29)
![a = 9.76 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.76%20m%2Fs%5E2)
3)
Answer:
v = 29.7 m/s
Explanation:
acceleration of the rocket is given as
![a = 90 m/s^2](https://tex.z-dn.net/?f=a%20%3D%2090%20m%2Fs%5E2)
time taken by the rocket
t = 0.33 min
final speed of the rocket is given as
![v_f = v_i + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20at)
![v_f = 0 + (90)(0.33)](https://tex.z-dn.net/?f=v_f%20%3D%200%20%2B%20%2890%29%280.33%29)
![v_f = 29.7 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2029.7%20m%2Fs)
4)
Answer:
Part 1)
y = 25.95 m
Part 2)
d = 6.72 m
Explanation:
Part 1)
As it took t = 2.3 s to hit the water surface
so here we will have
![y = \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![y = \frac{1}{2}(9.81)(2.3^2)](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7D%289.81%29%282.3%5E2%29)
![y = 25.95 m](https://tex.z-dn.net/?f=y%20%3D%2025.95%20m)
Part 2)
Distance traveled by it in horizontal direction is given as
![d = v_x t](https://tex.z-dn.net/?f=d%20%3D%20v_x%20t)
![d = 2.92 \times 2.3](https://tex.z-dn.net/?f=d%20%3D%202.92%20%5Ctimes%202.3)
![d = 6.72 m](https://tex.z-dn.net/?f=d%20%3D%206.72%20m)