Answer:
THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.
Explanation:
Using
Ca VA / Cb Vb = Na / Nb
Ca = 0.0500 M
Va = 35 mL
Cb = 0.0200 M
Vb = unknown
Na = 2
Nb = 1
Equation for the reaction:
Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O
So therefore, we make Vb the subject of the equation and solve for it
Vb = Ca Va Nb / Cb Na
Vb = 0.0500 * 35 * 1 / 0.0200 * 2
Vb = 1.75 / 0.04
Vb = 43.75 mL
The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL
Force = mass x gravity
Force = 20 kg x 9.8 m/s²
Force = 196 Newtons
Answer A
hope this helps!
Answer:
Explanation:
Given that,
The distance between the centers of the two oxygen atoms in an oxygen molecule is 
.
We need to convert this distance in inches.
We know that,
1 cm = 0.393 inches
We can solve it as follows :
So, the distance between the centers of the two oxygen atoms is 
.
