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horrorfan [7]
2 years ago
11

For the reaction N2+3H2⇌2NH3, the metals Fe and Mo used as catalyst. which of the following is NOT a reason that catalysts have

no effect on the equilibrium state?
A. In the presence of a catalyst, the same amounts of reactants and products will be formed as would form in the uncatalyzed reaction.
B. The addition of a catalyst speeds the rate of both the forward and reverse reactions, resulting in no change to the equilibrium.
C. Catalysts reduce the required activation energy and allow a reaction to reach equilibrium more quickly.
D. Catalysts get used up in the formation of the product.
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
7 0
D. Catalysts get used up in the formation of the product.

Catalysts are never used up in a reaction.
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The same sample of gas at different temperatures shows that at low

temperatures, most molecules have speeds close to their average

speed.

<h3>What does the Maxwell-Boltzmann distribution graph show?</h3>

Put simply, a Maxwell-Boltzmann distribution graph shows how the energy of gas particles varies within a system.

This is solely a measurement of the speeds of particles because kinetic energy is directly related to speed.

The Maxwell-Boltzmann distribution in chemistry is the subject of this article.

We will begin by describing how to read a graph of the Maxwell-Boltzmann distribution. This will involve taking a closer look at things like the typical energy and the most likely energy.

The graph will then be changed under various circumstances, such as when a catalyst is added or the temperature is raised.

The Maxwell-Boltzmann distribution, which we previously mentioned, is a probability function that depicts the distribution of energy among the particles of an ideal gas. (For more information on this topic, see Chemical Kinetics.)

To learn more about Maxwell distribution, refer

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8 0
1 year ago
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What is the measurement 1043. L rounded off to two significant figures?
Sloan [31]

Answer:

1000L

Explanation:

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3 0
3 years ago
Show the calculation of the mass (grams) of a 14.5 liter gas sample with a molecular weight of 82 when collected at 29°C and 740
mote1985 [20]

Answer:

In this conditions, the gaswll weight 46.74 g.

Explanation:

The idal gas law states that:

PV = nRT,

P: pressure = 740 mmHg = 0.97 atm

V: volume = 14.5 L

n: number of moles

R: gas constant =0.08205 L.atm/mol.K

T: temperature = 29°C = 302.15K

n = \frac{PV}{RT} \\n = \frac{0.97x14.5}{0.082 x 302.15 } \\n = 0.57 mol

1 mol gas ___ 82 g

0.57 mol gas __ x

x = 46.74 g

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3 years ago
How Mendeleev's systematic approach resulted in the development of his Periodic Table of elements.
tensa zangetsu [6.8K]
I just wanna know what does that even mean
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3 years ago
Can someone help quick
alina1380 [7]

Answer:

Sodium

(Na)

Just count the electrons and search which atom it is.

7 0
2 years ago
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