Answer:
Explanation:
Molar ratio for Sg : FeS = 1:8
If there are 0.3 moles for Sg
Therefore, 0.3 × 8 =2.4 moles of FeS
Mass = Moles/ Mr
Mr of FeS = 56+32=88
So mass = 2.4/88
Mass= 0.027g
Answer:
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Explanation:
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Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).
Explanation:
This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7
Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4
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