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3 years ago

Help plz i am confusion plzzzz

Mathematics

2 answers:

zmey [24]3 years ago

8 0

Answer:

Do C and D (Option 3 + 4)

frosja888 [35]3 years ago

6 0

D, -4x+5=-4x-5 is no Solution because you do +4x on both which is then 5=-5 which is false so no solution

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A lock has two digit numeric code, with the numbers 1 through 7 available for each digit of the code. Note that numbers can be r

lubasha [3.4K]

If there is 2 digits and 7 numbers the combos would be:
1,1 2,1 3,1 4,1 5,1 6,1 7,1
1,2 2,2 3,2 4,2 5,2 6,2 7,2
1,3 2,3 3,3 4,3 5,3 6,3 7,3
1,4 2,4 3,4 4,4 5,4 6,4 7,4
1,5 2,5 3,5 4,5 5,5 6,5 7,5
1,6 2,6 3,6 4,6 5,6 6,6 7,6
1,7 2,7 3,7 4,7 5,7 6,7 7,7

Therefore there are 49 possible combinations :)

7 0

2 years ago

Macy currently has a balance of $3,418.82 in an account earning simple interest. Eighteen years ago she opened the account with

Elis [28]

The simple interest is 1.79726

8 0

3 years ago

If f(x) =3x-5 them find values of f(3) and f(-7). please explain step by step

LenKa [72]

Answer:

f(3) = 4

f(-7) = -26

Step-by-step explanation:

Hi there!

$f(x) =3x-5$

To find f(3), replace every x with 3:

$f(3) =3(3)-5\\f(3) =9-5\\f(3) =4$

Therefore, f(3)=4.

$f(x) =3x-5$

To find f(-7), replace every x with -7:

$f(-7) =3(-7)-5\\f(-7) =-21-5\\f(-7) =-26$

Therefore, f(-7)=-26.

I hope this helps!

8 0

2 years ago

Nate solve the problem 3×5 = 15 by writing and solving 15÷5 = 3 explain why Nate method works

dmitriy555 [2]

It's shust the opposite

6 0

2 years ago

Read 2 more answers

Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t

schepotkina [342]

Answer:

(A) Set A is linearly independent and spans $R^3$ . Set is a basis for $R^3$ .

Step-by-Step Explanation

Definition (Linear Independence)

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

Definition (Span of a Set of Vectors)

The Span of a set of vectors is the set of all linear combinations of the vectors.

Definition (A Basis of a Subspace).

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors $A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)$ , we are to decide which of the given statements is true:

In Matrix $A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)$ , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. $R^3$ has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans $R^3$ .

Therefore Set A is linearly independent and spans $R^3$ . Thus it is basis for $R^3$ .

8 0

2 years ago