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3 years ago

A model of an airplane is 8 inches long. If the actual

Mathematics

1 answer:

andrew11 [14]3 years ago

8 0

Answer:

The answer is

Step-by-step explanation:

just multiply 4.5 by 8 and you get 36

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1. MAKE SURE TO WAIT UNTIL YOU HAVE MATH CLASS BEFORE STARTING 5 points

andrew-mc [135]

Answer:

340/4

Step-by-step explanation:

i beleive the answer would be 340 = 4 but if 340/4 is an option you could choose it.

8 0

2 years ago

What is the slope of this line ?<br> Answers : 2, 1/2, 4, and -4

xxMikexx [17]

Answer:

Step-by-step explanation:

$slope =\frac{rise}{run}$

$\frac{rise}{run}=\frac{2}{1} =2$

<em>good luck, i hope this helps :)</em>

3 0

2 years ago

Read 2 more answers

PLEASE HELP! ITS DUE SOON AND IM STUCK ON THE LASY QUESTION!

Andrej [43]

Answer:

2k + 4 > k + 11

Step-by-step explanation:

Keywords:

more - addition

twice - multiplication

greater than - >

sum - addition

4 more than twice the number k

2k + 4

Greater than

Sum of k and 11

k + 11

2k + 4 > k + 11

Solve for k if needed.

2k + 4 > k + 11

2k > k + 7

k > 7

Best of Luck!

6 0

3 years ago

@bobross plz help I have another question

enot [183]

Answer:

Average velocity is 32 miles/hr.

Step-by-step explanation:

Given that a particle moves on a line away from its initial position so that after t hours it is $s=6t^2+2t$ miles from its initial position.

We have to find the average velocity of the particle over the interval [1, 4].

As, average velocity is the change is position over the change in time.

$s(4)=6(4)^2+2(4)=104$

$s(1)=6(1)^2+2(1)=8$

∴ $\text{Average Velocity=}\frac{s(4)-s(1)}{4-1}$

= $\frac{104-8}{3}=\frac{96}{3}=32miles/hr$

Hence, average velocity is 32 miles/hr.

6 0

3 years ago

Read 2 more answers

An astronaut on the moon throws a baseball upward. the astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is

BabaBlast [244]

Answer:

Step-by-step explanation:

This was answered in question #24217201. It's the exact same question, but you forgot to put what parts A and B are. The answers and the work are there.

5 0

3 years ago