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2 years ago

If ABC is reflected

Mathematics

1 answer:

Anna [14]2 years ago

4 0

Answer:

option b is the answer of your question

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Need help with number 3 8/t; t = 4

LUCKY_DIMON [66]

Hello

x - 7

for x = 23 = 23 - 7 = 16

3 a - b = 12 - 6 = 6

8/t = 8/4 = 2

9 + m = 9 + 1.5 = 10.5

1/2 w + 2 = 1/2 x 1/9 + 2 = 1/18 + 2 = 1/18 + 36/18 = 37/18

5 ( 6.2 + z ) = 50

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2 years ago

Mark reduce the size of a photo to a height of 4 inches. What is the new width if it was originally 16 inches tall and 8 inches

uranmaximum [27]

Answer:

Step-by-step explanation:

new height is ¼ of original height

new width = ¼×8 = 2 inches

4 0

2 years ago

Read 2 more answers

Evaluate the expression if y=4.4 and z= 12 z2+ 8y

Evgen [1.6K]

Answer: 59.2

Step-by-step explanation:

Take your equation

z2+8y

Now plug in the values given

(12)2+8(4.4)

24+35.2

59.2

5 0

2 years ago

I’ll mark the brainiest

baherus [9]

Answer:

AB=3.16

BC=6.32

CD=3.16

AD6.32

Step-by-step explanation:

6 0

2 years ago

The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is cl

gladu [14]

Consider the attached ellipse. Let the sun be at the right focus. Then perihelion is at right vertex on the x-axis and aphelion is at the left vertex on the x-axis.

The distances:

from perihelion to the sun in terms of ellipse is a-c;
from aphelion to the sun in terms of ellipse is a+c.

Then

$\left\{\begin{array}{l}a-c=741,000,000\\a+c=817,000,000\end{array}\right.$

Add these two equations:

$2a=1,558,000,000 \\ \\a=779,000,000$

and subtract first equation from the second:

$2c=76,000,000 \\ \\c=38,000,000.$

Note that $b=\sqrt{a^2-c^2},$ thus

$b=\sqrt{779,000,000^2-38,000,000^2}=\sqrt{605,397,000,000,000,000}.$

The equation for the planet's orbit is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\Rightarrow \dfrac{x^2}{606,841,000,000,000,000}+\dfrac{y^2}{605,397,000,000,000,000}=1.$

7 0

3 years ago