A recent study investigated whether renowned violinists were able to classify the age of a violin. In the study, violins constru
cted before 1900 and violins constructed after 2010 were used. The violinists played each violin and were asked to classify the violin as old (constructed before 1900) or new (constructed after 2010). The responses are shown in the following table.
Which of the following statements is supported by the results in the table?
1.)The proportion of all new violins that are correctly classified is equal to the proportion of all old violins that are correctly classified.
2.)The proportion of all new violins that are incorrectly classified is equal to the proportion of all old violins that are correctly classified.
3.)The proportion of all incorrectly classified violins that are old is equal to the proportion of all correctly classified violins that are new.
4.)The proportion of all incorrectly classified violins that are new is equal to the proportion of all correctly classified violins that are new.
5.)The proportion of all correctly classified violins that are old is equal to the proportion of all new violins that are incorrectly classified.
Which of the following statements is supported by the results in the table?
1.)The proportion of all new violins that are correctly classified is equal to the proportion of all old violins that are correctly classified.
2.)The proportion of all new violins that are incorrectly classified is equal to the proportion of all old violins that are correctly classified.
3.)The proportion of all incorrectly classified violins that are old is equal to the proportion of all correctly classified violins that are new.
4.)The proportion of all incorrectly classified violins that are new is equal to the proportion of all correctly classified violins that are new.
5.)The proportion of all correctly classified violins that are old is equal to the proportion of all new violins that are incorrectly classified.
1 answer:
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c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is
and using the result of part (a) again, the volume is