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3 years ago

10

15 POINTS) Frank is surveying shoppers about their use of the new food court in a mall. Which question in his survey is a statis

tical question?
Group of answer choices

How many hours do you spend at the food court each month?

Where is the food court located in the mall?

How many restaurants are there in the food court?

Who is the manager of the food court?

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

Ok I believe it’s the 1st one

Step-by-step explanation:

Frank has to ask everyone how much time they spend in the mall each month

He has to collect info

Hope I helped :)

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Read 2 more answers

For some transformation having kinetics that obey the Avrami equation (Equation 10.17), the parameter n is known to have a value

Nikolay [14]

Given Information:

constant = n = 1.7

transformation time 50% completion = t₅₀ = 100 s

Required Information:

transformation time 99% completion = t₉₀ = ?

Answer:

transformation time 99% completion = $t_{90} = 202.75$ $seconds$

Step-by-step explanation:

The Avrami equation is used to model the transformation of solids that is from one phase to another provided that temperature is constant.

The equation is given by

$y=1 - e^{{-kt}^{n}}$

Where t is the transformation time in seconds and n, k are constants.

Let us first find the constant k, since after 100 s transformation is 50% complete,

$0.50=1 - e^{{-k*100}^{1.7}}$

$0.50 - 1= - e^{{-k*100}^{1.7}}$

$-0.50= - e^{{-k*100}^{1.7}}$

$0.50 = e^{{-k*100}^{1.7}}$

Take ln on both sides,

$ln(0.50) = ln(e^{{-k*100}^{1.7}})$

$-0.693 = -k*100}^{1.7}$

$0.693 = k*100}^{1.7}$

$k = 0.693/100}^{1.7}$

$k = 2.759*10^{-4}$

Now we can find out the time when the transformation is 99% complete.

$0.90=1 - e^{{-kt}^{n}}$

$0.90 - 1= - e^{{-k*t}^{n}}$

$-0.10= - e^{{-kt}^{n}}$

$0.10 = e^{{-kt}^{n}}$

Take ln on both sides,

$ln(0.10) = ln(e^{{-k*t}^{n}})$

$-2.303 = -kt}^{n}$

$\frac{2.303}{k} = t^{n}$

$\frac{2.303}{2.759*10^{-4} } = t^{n}$

Again take ln on both sides

$ln(\frac{2.303}{2.759*10^{-4} }) =ln( t^{n})$

$9.03 = nln(t)$

$\frac{9.03}{n} = ln(t)$

$\frac{9.03}{1.7} = ln(t)$

$5.312 = ln(t)$

Take exponential on both sides

$e^{5.312} = e^{ln(t)}$

$202.75 = t$

$t = 202.75$ $seconds$

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